A Cu-30% Zn brass plate, originally 1.20 inches thick, is desired to have a yield strength greater than 50,000psi and a percent elongation of at least 15%. The final geometry of the plate will be obtained by means ofcold work. What range of final thicknesses is possible to obtain under the given conditions? The effect ofpercent cold work on Cu-3096 Zn brass properties is shown below.10080Resistencia a la tensión (ksi)60Límite elástico (ksi)20Porcentaje de elongación2040 6080Porcentaje de trabajo en fríoPropiedad

Answered: Image /qna-images/answer/108330c2-991e-48c6-88d0-3cd47098ef2d.jpg

Answered: A Cu-30% Zn brass plate, originally…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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Please draw each scenario using the TTT diagram
1 You want to produce a Brass plate that is 0.25" thick with a yield stress 50 ksi which corresponds to 37.5% cold work. The initial plate thickness is 1.0". The maximum cold work per step is 60%. What are the cold work and annealing steps that are necessary to achieve the desired result?
Sintered silicon nitride parts are expected to experience tensile stresses 50% of the ultimate tensile strength of the material. What will be the maximum allowable size of internal flaws for these parts not to fail in service? Given the following properties of the material: Specific surface energy: 0.3 J/m2 its Youngs Modulus: 304 GPa Ultimate tensile Strength: 570 MPa Select one: a. 1.43 µm b. 0.71 µm c. 15 µm d. 85 µm e. 9.5 µm
Consider the tensile stress strain curves in Figure 8-20 labeled 1 and 2 and answer the following questions. These curves are typical of metals. Consider each part as a separate question that has no relationship to previous parts of the question. (a) Which material has the larger work hardening exponent? How do you know? (b) Samples 1 and 2 are identical except that they were tested at different strain rates. Which sample was tested at the higher strain rate? How do you know? (c) Assume that the two stress strain curves represent successive tests of the same sample. The sample was loaded, then unloaded before necking began, and then the sample was reloaded. Which sample represents the first test: 1 or 2? Haw do you know?
A single crystal of aluminum is oriented for a tensile test such that its slip plane normal makes an angle of 28.1° with the tensile axis. Three possible slip directions make angles of 62.4°, 72.0°, and 81.1° with the same tensile axis. (a) Which of these three slip directions is most favored? (b) If plastic deformation begins at a tensile stress of 1.95 MPa (280 psi), determine the critical resolved shear stress for aluminum.
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2.) Two previously undeformed specimens of the same metal are to be plastically deformed by reducing their cross-sectional areas. One has a circular cross section, and the other is rectangular; during deformation the circular cross section is to remain circular, and the rectangular is to remain as such. Their original and deformed dimensions are as follows: Circular Rectangular (diameter, mm) (тm) Original dimensions Deformed dimensions 18.0 20 x 50 15.9 13.7 × 55.1 Which of these specimens will be the hardest after the plastic deformation? a) The deformed circular specimen will be harder b) The deformed rectangular specimen will be harder c) Both will have the same hardness d) Both would brake e) No estimation can be made for such process
The lower yield point for a certain plain carbon steel bar is found to be 135 MPa, while a second bar of the same composition yields at 260 MPa. Metallographic analysis shows that the average grain diameter is 50 µm in the first bar and 8 µm in the second bar. Predict the grain diameter needed to cause a lower yield point of 205 MPa.
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The figure shows two work pieces of steel of 0.15 %C and 1.2 %C with different dimensions. Compare between them regarding:- 1- The existed phases and the expected mechanical properties of each. 2- Give 5 important applications for each alloy. 3- The stages of Normalizing treatments for each one. 900 800 1 Aj = 727°C 0.0218 0.77 700 Dimensions of (1.5*1.5*1.5) inch Dimensions of (1*1*1) inch 0.2 0.4 0.6 0.8 1.0 1.2 1.4 6.67 Weight percent carbon Temperature ("C)
A hypothetical metal alloy has a grain diameter of 2.4 × 10-2 mm. After a heat treatment at 575°C for 500 min, the grain diameter has increased to 5.6 × 10-2 mm. Compute the time required for a specimen of this same material (i.e., do = 2.4 × 10-² mm) to achieve a grain diameter of 5.5 x 10-2 mm while being heated at 575°C. Assume the n grain diameter exponent has a value of 2.2. i min
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