Question 2.(a)A cylindrical rod of length 120 mm and 15.0 mm diameter, is to bedeformed using a tensile load of 35 kN. It must not experience eitherplastic deformation or a diameter reduction of more than 1.2 x 102 mm.Of the materials given in Table 2a, which are possible candidates?Justify your answers.MaterialModulus of ElasticityYield Strength Poisson's(MPa x10³)(MPa)RatioAluminium alloy702500.33Titanium alloy1058500.36Steel alloy2055500.27Magnesium alloy451700.29[50%]

titanium alloy and steel alloy are possible candidatesif you have any doubts please comment here

Answered: Question 2. (a) A cylindrical rod of…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

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You are given a square rod of 6061-T6 aluminum (cross-section = 4mm X 4mm, length = 2.3m). The material has a Young’s modulus of 72 GPa. If a compressive load of 3 kN is applied parallel to the 2.3m dimension, what is the resulting engineering normal strain?
A tensile force of 120 kN is applied on a 0.02-m diameter and 2-m long rod. After applying the load, the diameter of the rod decreases to 0.01998 m and the length increases to 2.01 m. The engineering stress on that rod is?
For some metal alloy, the following engineering stresses produce the corresponding engineering plastic strains prior to necking. On the basis of this information, what engineering stress (in MPa) is necessary to produce an engineering plastic strain of 0.250? Engineering stress (MPa) Engineering strain 217 232 0.176 0.301
Please answer in proper units for ALL steps.
4. A titanium alloy (Ti-5Al-2.5Sn) specimen with the dimensions shown below is subjected to a uniaxial tensile load of 1500 N. (a) Determine if the deformation is entirely elastic. (b) What is the extension and gauge length (in mm) under this load? You may assume a Modulus of Elasticity of 110 GPa and a yield strength of 760 MPa. 13 mm 45 mm 9 mm R8 mm/ 40 mm
please provide explanation and formula (as much detail as possible) the picture include question and the table which you need to use. Final answer should be 5%
Question 1 You are working on a design team at a small orthopaedic firm. You have been asked to select a cobalt- chrome-molybdenum (CoCr) material that will not experience plastic deformation under a specific mechanical test, as follows... A tensile stress is applied along the long axis of a solid cylindrical rod that has a diameter of 10 mm. An applied load of some magnitude F produces a 7x10-³ mm change in diameter (see figure below, original shape is blue, elongated shape is unshaded). Q1E: Of those two materials (F75 CoCr alloy (as cast) and F90 CoCr alloy (hot forged)), which materials would you select to assure that the deformation is entirely elastic (No yield!)?
4. The mechanical properties of a given titanium alloy (Ti-6Al-4V) are E = 114 GPa, σy = 880 MPa and Kic = 75 MPa√m. What is the approximate plastic zone size? How large must a part be made if we want to test its K₁ using LEFM?
How does the resilience of this material compare to its toughness?
19 Consider a cylindrical specimen of some hypo- thetical metal alloy that has a diameter of 10.0 mm (0.39 in.). A tensile force of 1500 N (340 lb;) produces an elastic reduction in diameter of 6.7 x 104 mm (2.64 × 10 in.). Compute the elastic modulus of this alloy, given that Poisson's ratio is 0.35.
A steel rod 22 mm in diameter and 1000 mm long is required to have an elastic strain energy of 90 N.m. What should be the yield strength of the material if its modulus of elasticity is 2.1x105 MPa? Hint: Elastic strain energy is related with the resilience of the material.
A tensile test for a copper specimen has been performed and the following data are obtained. - Percentage of Elongation = 60 % - Percentage of Reduction in Area = 36 % - Final length after fracture = 35.2 mm - Final Diameter after fracture = 3.54 mm & - Ultimate stress = 439 MPa i) Initial Length (in mm) = ii) Final Area (in mm2) = iii) Initial Area (in mm2) =

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