A converging lens (f 24.0 cm) is located 56.0 cm to the left of a diverging lens (f2 =-28.0 cm). An object is placed to the left of the converging lens, and the final image produced by the two-lens combination lies 20.7 cm to the left of the diverging lens. How far is the object from the converging lens? 47.32 cm
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- A lighted candle is placed 39.0 cm in front of a diverging lens. The light passes through the diverging lens and on to a converging lens (f = 10.0 cm) that is placed 5.00 cm from the diverging lens. The final image is real, inverted, and 44.0 cm beyond the converging lens. Find the focal length of the diverging lens.A diverging lens with focal length |f = 18.0 cm produces an image with a magnification of +0.620. What are the object and image distances? (Include the sign of the value in your answers.) cm cm object distance image distanceA glass (n=1.5) biconvex lens has radii of curvature of +15 cm and -18 cm. If an object is placed at 10 cm left of the left surface of the lens, what is the image distance? Calculate the magnification and orientation of the image.
- The focal length of a diverging lens is negative. If f= -26 cm for a particular diverging lens, where will the image be formed of an object located 53 cm to the left of the lens on the optical axis? cm to the left of the lens What is the magnification of the image?On one side of a diverging lens of focal length 59.0 cm, you position an object of height 3.92 cm somewhere along the principal axis. The resultant image has a height of 2.74 cm. How far from the lens is the object located? 17.8 cm 25.4 cm 43.2 cm 33.0 cmA converging lens is placed 36.0 cm to the right of a diverging lens of focal length 7.0 cm. A beam of parallel light enters the diverging lens from the left, and the beam is again parallel when it emerges from the converging lens. Calculate the focal length of the converging lens. f = _____ cm
- Two identical diverging lenses are separated by 18 cm. The focal length of each lens is -8.0 cm. An object is located 4.0 cm to the left of the lens that is on the left. Determine the final image distance relative to the lens on the right. cmA 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 7.80 cm. A diverging lens of focal length –16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position 7.5 cm in front of the second lens v 0.5466 height Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm Is the image inverted or upright? upright O inverted Is the image real or virtual? real virtualThe projection lens in a certain slide projector is a single thin lens. A slide 24.5 mm high is to be projected so that its image fills a screen 1.77 m high. The slide-to-screen distance is 2.93 m. (a) Determine the focal length of the projection lens. mm (b) How far from the slide should the lens of the projector be placed to form the image on the screen? mm