A converging lens (f₁ = 24.0 cm) is located 56.0 cm to the left of a diverging lens (f2 = -28.0 cm). An object is placed to the left of the converging lens, and the final image produced by the two-lens combination lies 20.9 cm to the left of the diverging lens. How far is the object from the converging lens? do1 = i

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Chapter1: Units, Trigonometry. And Vectors
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**Problem: Two-Lens System**

A converging lens (\( f_1 = 24.0 \, \text{cm} \)) is located \( 56.0 \, \text{cm} \) to the left of a diverging lens (\( f_2 = -28.0 \, \text{cm} \)). An object is placed to the left of the converging lens. The final image produced by the two-lens combination lies \( 20.9 \, \text{cm} \) to the left of the diverging lens. How far is the object from the converging lens?

\[ d_{o1} = \]

*Note: This setup involves calculating the object distance from the converging lens using the lens formula and considering the subsequent effects of the diverging lens on the image position.*
Transcribed Image Text:**Problem: Two-Lens System** A converging lens (\( f_1 = 24.0 \, \text{cm} \)) is located \( 56.0 \, \text{cm} \) to the left of a diverging lens (\( f_2 = -28.0 \, \text{cm} \)). An object is placed to the left of the converging lens. The final image produced by the two-lens combination lies \( 20.9 \, \text{cm} \) to the left of the diverging lens. How far is the object from the converging lens? \[ d_{o1} = \] *Note: This setup involves calculating the object distance from the converging lens using the lens formula and considering the subsequent effects of the diverging lens on the image position.*
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