An object is placed 20 cm to the left of a converging lens of focal length 30 cm. A diverging lens of focal length 15 cm is 25 cm to the right of the converging lens. Find the position and magnification of the final image. Object f₁ £₂
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- A converging lens (f₁ = 24.0 cm) is located 56.0 cm to the left of a diverging lens (f2 = -28.0 cm). An object is placed to the left of the converging lens, and the final image produced by the two-lens combination lies 20.9 cm to the left of the diverging lens. How far is the object from the converging lens? do1 = iConverging lenses A and B, of focal lengths 8.0 cm and 6.0 cm, respectively, are placed 36.0 cm apart. Both lenses have the same optic axis. An object 8.0 cm high is placed 12.0 cm to the left of lens A. Find the position, size, and orientation of the image produced by the lenses in combination.A diverging lens with focal length |f = 18.0 cm produces an image with a magnification of +0.620. What are the object and image distances? (Include the sign of the value in your answers.) cm cm object distance image distance
- Two converging lenses, each of focal length 15.1 cm, are placed 40.0 cm apart, and an object is placed 30.0 cm in front of the first lens. Where is the final image formed? The image is located 9.6| x 26.3 Your response differs from the correct answer by more than 10%. Double check your calculations. cm in front of the second lens. in front of the second lens. What is the magnification of the system? M = |-3.167 X -2.78 Your response differs from the correct answer by more than 10%. Double check your calculations.X Need Help? Read It2. A diverging lens (focal length f₁ = -16.0 cm) is placed a distance of d = 32.0 cm to the left of a converging lens (focal length f2 = 8.00 cm). An object is placed p₁ = 20.0 cm to the left of the diverging lens and has a height of h 1 13.0 cm. (a) Where is the image formed by the diverging lens (i.e. what is qi)? What is this image's height and is it upright or inverted? Does this image become a real or virtual object for the converging lens? (b) Where is the final image (i.e. what is q2)? Is it real or virtual? What is this image's height and is it upright or inverted? (c) On the figure below, draw a ray diagram of this situation. fi f2 f2A diverging lens is located 14 cm to the left of a converging lens. A 3.44-cm-tall object stands to the left of the diverging lens, exactly at its focal point. Determine the distance of the final image relative to the converging lens, in cm. Diverging lens 1 focal length = -7 cm Converging lens 2 focal length = 32 cm Object F1 Lens 1 Round to nearest whole number Lens 2 Eye A
- An object with a height of -0.040 m points below the principal axis (it is inverted) and is 0.200 m in front of a diverging lens. The focal length of the lens is -0.27 m. (Include the sign of the value in your answers.) (a) What is the magnification? (b) What is the image height? m (c) What is the image distance? mTwo lenses are mounted d = 39 cm apart on an optical bench. The focal length of the first lens is f1 = 9.8 cm and that of the second lens is f2 = 3.1 cm. An object of height ho = 4.9 cm is placed at a distance of do = 24 cm in front of the first lens. Now consider the two-lens system and the final image it forms, i.e., the image created by the second lens. What is the distance, in centimeters, between the object and its final image? D =?On one side of a diverging lens of focal length 42.7 cm, you position an object of height 3.27 cm somewhere along the principal axis. The resultant image has a height of 1.31 cm. How far from the lens is the object located? 51.1 cm 63.9 cm O 102.2 cm O 89.5 cm
- A lens of focal length +24.0 cm is at x 0, and a second lens of focal length -24.0 cm is located at x = 16.0 cm. Let the positive x-direction be to the right. At what position x is the final image of an object that is 48.0 cm to the left of the positive lens? cm X = What is the magnification m of the image?.(Remember that magnification can be positive or negative.) m = The image is and virtual real Where should your eye be located and directed to see the image? O looking left from the right of both lenses looking left from between the lenses looking right from between the lenses O looking right from the left of both lenses Question Source: Freedman College PhysicAn object is located 16.6 cm to the left of a diverging lens having a focal length f = −32.4 cm. What is the magnification of the image? Group of answer choices 0.661 2.13 0.346 1.17Can you help me calculate the height. I kept getting it wrong.