▾ Part HWhat is the image distance?Express your answer in centimeters, as a fraction or to three significant figures.15. ΑΣΦs' =SubmitRequest AnswerPoz?cm Consider an object with s = 12 cm that produces an image with s' = 15 cm. Note that wheneveryou are working with a physical object, the object distance will be positive (in multiple opticssetups, you will encounter "objects" that are actually images, but that is not a possibility in thisproblem). A positive image distance means that the image is formed on the side of the lens fromwhich the light emerges.▾ Part AFind the focal length of the lens that produces the image described in the problem introductionusing the thin lens equation.Express your answer in centimeters, as a fraction or to three significant figures.f = 6.67 cmSubmit Previous Answers

We can use the lens equation to solve this problem. The lens equation relates the object distance,…

Answered: Consider an object with 8 = 12 cm that…

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Having become stranded in a remote wilderness area, you must live off the land while you wait for rescue. One morning, you attempt to spear a fish for breakfast. h You spot a fish in a shallow river. Your first instinct is to aim the spear where you see the image of the fish, at an angle $ = 43.40° with respect to the vertical, as shown in the figure. However, you know from physics class that you should not Image throw the spear at the image of the fish, because the actual location of the fish is farther down than it appears, at a depth H of H 0.9500 m. This means you must decrease the angle at which you throw the spear. This slight decrease in the angle is represented as a in the figure. If you throw the spear from a height h : 1.200 m above the water, calculate the angle decrease a. Assume that the index of refraction is 1.000 for air and 1.330 for water.
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Ving you must live off the land while you wait for rescue. One morning, you attempt to spear a fish for breakfast. You spot a fish in a shallow river. Your first instinct is to aim the spear where you see the image of the fish, at an angle $ = 43.40° with respect to the vertical, as shown in the figure. %3D However, you know from physics class that you should not Image throw the spear at the image of the fish, because the actual location of the fish is farther down than it appears, at a depth H. of H = 0.9000 m. This means you must decrease the angle at which you throw the spear. This slight decrease in the angle is represented as a in the figure. If you throw the spear from a height h = 1.150 m above the %3D water, calculate the angle decrease a. Assume that the index of refraction is 1.000 for air and 1.330 for water. 1.48 a = Incorrect