Galilean beam expander: A parallel beam of light enters a negative lens, diverges and enters a longer focal length positive lens of larger diameter. distance between lenses = 9.0 cm, Assume f1 = -12.0 cm and f2 = +21.0 cm, make a scaled ray diagram of the beam expander. Use algebra and ray tracing to find the lateral magnification of the instrument.
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Galilean beam expander: A parallel beam of light enters a negative lens, diverges and enters a longer focal length positive lens of larger diameter. distance between lenses = 9.0 cm, Assume f1 = -12.0 cm and f2 = +21.0 cm, make a scaled ray diagram of the beam expander. Use algebra and ray tracing to find the lateral magnification of the instrument.
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- An eraser is placed 1.33 cm in front of a thin convex lens with a focal length (f) of 5.65 cm. Calculate the eraser image's distance (di) from the lens. Record your answer as a positive number. di = cmA nearsighted woman can't see objects clearly beyond 41.7 cm (her far point). If she has no astigmatism and contact lenses are prescribed, what power and type of lens are required to correct her vision -3.134 X power Your response differs from the correct answer by more than 10%. Double check your calculations. diverging lens type of lens Need Help? Read ItNone
- Two converging lenses with focal lengths of 50 cm and 21 cm are 10 cm apart. A 3.9- cm-tall object is 25 cm in front of the 50-cm -focal-length lens. A. Calculate the distance between the final image and 21-cm-focal-length lens. B. Calculate the image height.a) An object is placed 40.0cm in front of a diverging lens with a focal length of 19.2 cm. Please provide your answers in units of cm if necessary. Find the image distance. I answered this part and I got -13 as an answer. But i can't solve this second part: b) Suppose the object is brought to a distance of 11.7 cm in front of the lens. Where is the image now with respect to its previous location? (Note: Ensure the sign convention you use is consistent by treating all image distances on the object side of the lens as negative.) c)How has the height of the image changed if the object is 80.7 cm tall? plz help me answer it. thanksAn object is placed a distance do = 6.0 cm in front of a positive (converging) lens of focal length f = 13.0 cm. Where is the image formed relative to the lens position (positive = to the right of the lens)? d₁ = What is the image magnification? m = cm Is the image upright or inverted? inverted upright no image is formed Is the image real or virtual? real O no image is formed O virtual o do
- Please help me with this question.An object that is 2.0 cm tall is located 5.0 cm behind the vertex of a converging lens with a focal length of 10 cm as shown in the diagram below. Which of the lettered choices below gives the correct image characteristics? Specifically, what willI be the height, orientation, and nature of the final image? 10 cm Object İ50 5.0 cm f Converging Lens a. 3.0 cm, inverted, real b.4.0 cm, upright, virtual c. 5.0 cm, upright, real d. 4.0 cm, inverted, virtual e. 2.5 cm, upright, virtual O O O O OA small insect is placed 5.40 cm from a 6.00-cm-focal-length lens. a) Calculate the position of the image. Follow the sign conventions. Express your answer using two significant figures and include the appropriate units. b) Calculate the angular magnification. Express your answer using two significant figures.
- Work with your neighbors to fill in the table below. If a number has (+) written in front of it, then you must determine if the number should be positive or negative. mirror type concave focal radius of length curv. (+)20 cm +20 cm -40 cm object image magnifi- distance distance cation +10 cm +10 cm +30 cm -10 cm 1.0 real or virtual? inverted. or not?HW8 Q3 A lens for a 35-mm camera has a focal length given by f = 46.0 mm. How close to the film should the lens be placed to form a sharp image of an object that is 5.00 m away? Express your answer in millimeters. What is the magnification of the image on the film?HW8 Q10 A magnifying glass is a single convex lens with a focal length of f= 13.0 cm. What is the angular magnification when this lens forms a (virtual) image at −∞? How far from the object should the lens be held? What is the angular magnification when this lens forms a (virtual) image at the person's near point (assumed to be 25 cm)? How far from the object should the lens be held in this case?