A nearsighted woman can't see objects clearly beyond 41.7 cm (her far point). If she has no astigmatism and contact lenses are prescribed, what power and type of lens are required to correct her vision. -3.134 X power Your response differs from the correct answer by more than 10%. Double check your calculations. diverging lens type of lens Need Help? Read It
A nearsighted woman can't see objects clearly beyond 41.7 cm (her far point). If she has no astigmatism and contact lenses are prescribed, what power and type of lens are required to correct her vision. -3.134 X power Your response differs from the correct answer by more than 10%. Double check your calculations. diverging lens type of lens Need Help? Read It
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Correcting Nearsightedness: Determining Lens Power and Type
#### Question:
A nearsighted woman can't see objects clearly beyond **41.7 cm** (her far point). If she has no astigmatism and contact lenses are prescribed, what power and type of lens are required to correct her vision?
#### Student's Response:
* **Power:** -3.134
* **Type of Lens:** Diverging lens
#### Feedback:
* The selected lens type is correct.
* The power of the lens you calculated is incorrect. **Your response differs from the correct answer by more than 10%. Double-check your calculations.**
#### Additional Help:
If you need more help understanding the problem and the calculations involved in determining the correct lens power, please refer to the available resources.
#### Need Help?
[Read It]
---
### Explanation of the Correct Approach
To correct nearsightedness, lenses with the appropriate negative power (diverging lenses) are required to extend the far point to infinity, allowing the person to see distant objects clearly.
1. **Determine the far point** (41.7 cm in this case).
2. **Use the lens formula:**
\[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \]
For glasses or contact lenses, the image distance (v) is set to infinity for distant objects, and the object distance (u) is the negative of the far point (-41.7 cm).
3. **Calculate the power (P) of the lens** using the formula for focal length (f):
\[ P = \frac{1}{f\ \text{(in meters)}} \]
Double-check the calculations to ensure accuracy and avoid discrepancies.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe33ed983-9f3f-4edc-a3fb-37efbd4f1fcf%2F8fd77bc6-9b39-4949-bd71-11de147d5b1d%2Fbjhx5hh_processed.png&w=3840&q=75)
Transcribed Image Text:### Correcting Nearsightedness: Determining Lens Power and Type
#### Question:
A nearsighted woman can't see objects clearly beyond **41.7 cm** (her far point). If she has no astigmatism and contact lenses are prescribed, what power and type of lens are required to correct her vision?
#### Student's Response:
* **Power:** -3.134
* **Type of Lens:** Diverging lens
#### Feedback:
* The selected lens type is correct.
* The power of the lens you calculated is incorrect. **Your response differs from the correct answer by more than 10%. Double-check your calculations.**
#### Additional Help:
If you need more help understanding the problem and the calculations involved in determining the correct lens power, please refer to the available resources.
#### Need Help?
[Read It]
---
### Explanation of the Correct Approach
To correct nearsightedness, lenses with the appropriate negative power (diverging lenses) are required to extend the far point to infinity, allowing the person to see distant objects clearly.
1. **Determine the far point** (41.7 cm in this case).
2. **Use the lens formula:**
\[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \]
For glasses or contact lenses, the image distance (v) is set to infinity for distant objects, and the object distance (u) is the negative of the far point (-41.7 cm).
3. **Calculate the power (P) of the lens** using the formula for focal length (f):
\[ P = \frac{1}{f\ \text{(in meters)}} \]
Double-check the calculations to ensure accuracy and avoid discrepancies.
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