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Create a ray diagram for eyeglasses that contain a diverging lens.
Assume you are looking at a 2 cm tall object that is 4 cm from the
lens. The focal length is 3 cm.
What type of vision are they used to correct? Give both names. How
do they do this? Explain.

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Can you please explain how...well...how this works. Can you draw a diagram or something? It seems like if you use m=v/u and enter 25 cm for v, then you're saying that the image is 25cm from whatever the rest of the system is in the equation. m is the magnification of the lens, so when you arrive at the value for u, that seems like it should be saying that if you put the iron 8.3 cm from the lens, then it will project the image 25 cm from the lens. Not 25 cm in front of your eyes. I don't understand how the answer ends up applying to the distance to the eyes. Is there some algebra that needs to be done to link the distance from the image to the distance to the eyes? By the way, what do v and u stand for? I know they're distances, but what words do the letters represent?
= 20.0 cm and fB 25.0 cm, Q3: A two-lens system. Two converging lenses, A and B, with focal lengths f are placed 80.0 cm apart, as shown in Figure. An object is placed 60.0 cm in front of the first lens. Determine (a) the position, and (b) the magnification, of the final image formed by the combination of the two lenses. F A A B ff TI TI பட B =
can you use the formulas from the picture? thank you
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