A contact lens is made of plastic with an index of refraction of 1.58. The lens has an outer radius of curvature of +2.06 cm and an inner radius of curvature of +2.53 cm. What is the focal length of th
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- When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.20 cm-tall object is 60.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of The eye's lens. Part A Find the location and height of the image (call it I₁) formed by the lens with a focal length of 40.0 cm. Enter your answers in centimeters separated by a comma. s₁, y = 120,2.40 cm Submit Correct Set Up: Apply Solve: Lens 1: m₁ = Previous Answers Part B $1 f₁ $1-f₁ $₂,|y₂| = 1 S s' 1 S +1/1 = = gives (60.0 cm) (40.0 cm) 60.0 cm-40.0 cm to each lens. m₁ 120 cm 60.0 cm = = -2.00 = Y'₁ Y1 120 cm and m2 $1…An optician is designing a contact lens. The material has is an index of refraction of 1.45. In order to yield the prescribed focal length, the optician specifies the following dimensions: inner radius of curvature = +2.60 cm outer radius of curvature = +1.98 cm where the inner radius of curvature describes the surface that touches the eye, and the outer radius of curvature describes the surface that first interacts with incoming light. What is the focal length of this contact lens (in cm)?e) 2.00 diopters An object is placed 32.0 cm in front of a converging lens and a concave mirror as shown in the figure. The focal length of the lens is 16.5 cm, and the focal length of the mirror is 23.5 17. cm. The distance between the lens and the mirror is 37.0 cm. What is the distance of the final image in reference to the mirror? a) -3.35 cm b) 34.1 cm c) 3.35 cm d) 2.61 cm e) 2.94 cm
- A convex lens (i.e. with R1 > 0 and R2 < 0 with left and right radii of curvature of magni- tudes 16.5 cm and 18.5 cm has an index of refraction n of 1.55. What is the focal length of the lens? О А. 15.9 сm ОВ. 23.1 ст О С. 30.3 сm O D. 44.8 cmThe lens in the figure below is made of glass of index 1.50 and have surfaces with radii of curvature of magnitude either 9.40 cm or 21.3 cm. Find the radii of curvature and the focal length of the lens.An optician is designing a contact lens. The material has is an index of refraction of 1.35. In order to yield the prescribed focal length, the optician specifies the following dimensions: inner radius of curvature = +2.60 cm outer radius of curvature = +2.06 cm where the inner radius of curvature describes the surface that touches the eye, and the outer radius of curvature describes the surface that first interacts with incoming light. What is the focal length of this contact lens (in cm)? answer in cm
- You are designing a lens to be made of glass with index of refraction 1.70. The first surface (the surface toward the object) is to be convex with radius of curvature 28.0 cm, and the focal length of the lens is to be 14.0 cm. (a) What must be the radius of curvature of the second surface (the surface away from the object)? (b) Will the second surface be concave or convex?6. A convex (converging) lens has a focal length of 12.5 cm. Where on the lens axis should an object be placed in order to get a vwtual, enlarged image with a magnification of 2.50?A symmetric double convex lens with a focal length of 26.0 cmcm is to be made from glass with an index of refraction of 1.52. What should be the radius of curvature for each surface? Express your answer to two significant figures and include the appropriate units.
- a converging lens has a focal length of 4.5cm. it forms an inverted image with an image distance of 5.5cm what is the magnification?One side of a lens is convex with radius of curvature 30 cm. The other side is concave with radius of curvature 50 cm. The index of refraction of the lens is 1.6. What is the focal length of the lens? Group of answer choices 130 cm, converging 130 cm, diverging 31 cm, converging 31 cm, divergingAn optician is designing a contact lens. The material has is an index of refraction of 1.60. In order to yield the prescribed focal length, the optician specifies the following dimensions: inner radius of curvature = +2.56 cm outer radius of curvature = +2.10 cm where the inner radius of curvature describes the surface that touches the eye, and the outer radius of curvature describes the surface that first interacts with incoming light. What is the focal length of this contact lens (in cm)?