On one side of a diverging lens of focal length 52.4 cm, you position an object of height 4.52 cm somewhere along the principal axis. The resultant image has a height of 3.62 cm. How far from the lens is the object located? 10.4 cm 13.0 cm 23.4 cm 16.9 cm
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Q: An object of height 10.0 cm is placed 20.0 cm away from a converging lens. The image is 30.0 cm…
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10.4 cm
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13.0 cm
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23.4 cm
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16.9 cm
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- On one side of a diverging lens of focal length 59.0 cm, you position an object of height 3.92 cm somewhere along the principal axis. The resultant image has a height of 2.74 cm. How far from the lens is the object located? 17.8 cm 25.4 cm 43.2 cm 33.0 cmOn one side of a converging lens of focal length 21.3 cm, you position an object of height 3.27 cm somewhere along the principal axis. The resultant image has a height of 11.77 cm. How far from the lens is the object located? 27.2 cm 10.9 cm 38.1 cm 21.8 cmYou place an object 21.2 cm in front of a diverging lens which has a focal length with a magnitude of 12.2 cm. Determine how far in front of the lens the object should be placed in order to produce an image that is reduced by a factor of 2.70.cm
- A system of two converging lenses forms an image of an arrow as shown. The first lens is located at x = 0 and has a focal length of f₁ = 8.8 cm. The second lens is located at x = x2 = 58.13 cm and has a focal length of f2 = 21 cm. The tip of the object arrow is located at (x,y) = (xo,Y)= (-12.3 cm, 6.9 cm). AY (X,Y) 1) What is x₁, the x-coordinate of image of the arrow formed by the first lens? cm Submit 2) What is y₁, the y-coordinate of the image of the tip of the arrow formed by the first lens? cm Submit Virtual and Inverted Virtual and Upright Submit X₂ cm Submit X 3) What is x3, the x co-ordinate of image of the arrow formed by the two lens system? cm Submit 5) What is the nature of the final image relative to the object? Real and Inverted Real and Upright ++++ 4) What is y3, the y-coordinate of the image of the tip of the arrow formed by the two lens system? + 6) Which of the following changes to the locations of the lenses would result in a virtual and inverted image of the…A 1.00-cm-high object is placed 4.30 cm to the left of a converging lens of focal length 8.45 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position 188.8 height 26.048 X cm in front of the second lens X cmAn object is 60.0 cm from a converging lens and the object is 1.00 cm tall. What is the poisition and height of the image if the focal length of the lens is 25.0 cm? The object is at 0.0233 cm and the height of the image will be 0.715 cm upright. The object is at 0.0233 cm and the height of the image will be 0.000388 cm inverted. The object is at 42.9 cm and the height of the image will be 0.000388 cm upright. The object is at 42.9 cm and the height of the image will be 0.715 cm inverted.
- Is the final image real or virtual? Is the final image upright or inverted?Mike holds a magnifying glass (convex lens) 5.00 cm above a sheet of paper. He looks at the writing on the page and notices that it is magnified by a factor of 3.00. What is the focal length of the lens he is using? a 2.00 cm b 4.00 cm c 7.50 cm d 3.75 cmYou place an object 21.4 cm in front of a diverging lens which has a focal length with a magnitude of 11.8 cm. Determine how far in front of the lens the object should be placed in order to produce an image that is reduced by a factor of 3.35. cm Additional Materials
- The object is located at a distance of 20 cm from the lens, which forms upright image double of the size of the object. What is the focal distance of the lens? O- 5 cm O +0.4 m 10 cm O +20 cm O-0.2 m O-40 cmA system of two lenses forms an image of an arrow at x = x3 = 57.4 cm. The first lens is a diverging lens located at x = 0 and has a focal length of magnitude f₁ = 11.5 cm. The second lens is located at x = x₂ = 25.4 cm and has an unknown focal length. The tip of the object arrow is located at (x,y) = (xo, Yo) = (-36 cm, 20.6 cm). (x,y) 1) What is x₁, the x-coordinate of image of the arrow formed by the first lens? cm Submit 2) What is y₁, the y-coordinate of the image of the tip of the arrow formed by the first lens? cm Submit X₂ Real and Inverted Real and Upright Virtual and Inverted Virtual and Upright cm Submit (+) 3) What is f2, the focal length of the second lens. If the lens is a converging lens, f2 is positive. If the lens is a diverging lens, f2 is negative. cm Submit + 4) What is y3, the y-coordinate of the image of the tip of the arrow formed by the two lens system? (+ 5) The positions of the two lenses are now interchnaged (i.e., the second lens is moved to x = 0 and the…8. On one side of a converging lens of focal length 59.1 cm, you position an object of height 3.02 cm somewhere along the principal axis. The resultant image has a height of 15.10 cm. How far from the lens is the object located? 70.9 cm 28.4 cm 92.2 cm 42.5 cm