A cone is resting on a tabletop as shown in the figure with its face horizontal. A uniform electric field of magnitude 4550 N/C points horizontally to the right. How much electric flux passes through the sloping side surface area of the cone?
Q: 60.0° 10.0 cm 30.0 cm 1 (a) Calculate the electric flux through the vertical rectangular surface of…
A:
Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.52 x…
A:
Q: When a piece of cardboard is held with its face perpendicular to a uniform electric field, the flux…
A:
Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.10 x…
A: Given E = 7.10×104 N/C
Q: A flat surface of area 3.20 m² is rotated in a uniform elec- tric field of magnitude E6.20 x 10 N/C.…
A: Given: Surface area A=3.20 m2, Electric field E=6.20×10 N/C. Required: Electric flux through the…
Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.58 x…
A: E = 6.58 x 104 N/C
Q: A 42.0-cm-diameter circular loop is rotated in a uniform electric field until the position of…
A:
Q: Two large copper plates facing each other have charge densities £4.00 C/r on the surface facing the…
A: Electric fLux: Electric flux can be defined as the scalar product of the electric field and the area…
Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.70 x…
A:
Q: A cube has sides of length L = 0.400 m. It is placed with one corner at the origin as shown in the…
A:
Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.22 x…
A: Magnetic flux
Q: A 45.0-cm-diameter circular loop is rotated in a uniform electric field until the position of…
A: Given that : d=45 cm =45 x 10-2 m ϕ=5.60 x 105 m2/C
Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.62 x…
A:
Q: The drawing shows an edge-on view of two planar surfaces that intersect and are mutually…
A: According to the question data Surface-1 area = A1 =1.4m2 Surface-2 area = A2 =4.1m2 Electric field…
Q: Consider the uniform electric field E = (2.5 j + 2.5 k) × 103 N/C. a) Calculate the electric flux…
A: Given: The uniform electric filed E is (2.5 j⏜ + 2.5 k⏜)×103 N/C. The radius of the circular area in…
Q: A figure shows a closed cylinder with a cross-sectional area A = 3.60 m2. The upper and lower…
A:
Q: An electric field, E = 477 N/C, passes through a circular loop, of area A = 0.485 m², at an angle of…
A: CONCEPT:
Q: A non-uniform thin rod is bent into an arc of radius R. The linear charge density λ of the rod…
A: Given, λ=λ0cosθ
Q: In the figure a nonconducting rod of length L = 8.42 cm has charge -q = -4.23 fC uniformly…
A: (a) The linear charge density of the rod will be:
Q: A electric field at 3.2 cm from the centre of a long copper rod of radius 0.6 cm has a magnitude 6.6…
A: Given value--- Electric field = 6.6 N/C. radius = 0.6 cm. We have to find--- What is the charge…
Q: A 96 cm diameter loop is rotated in a uniform electric field until the position of maximum electric…
A: E = flux /A d= 96cm A= π r2 = 0.7238 m2 Flux = 3.1 × 105 Nm2/C
Q: A flat sheet is in the shape of a rectangle with sides of lengths 0.2 m and 1.7 m. The sheet is…
A: Given that Length of the sheet L = 1.7 m Width of the sheet b = 0.2 m Uniform electric field E = 65…
Q: An electric field given by E = 5x i - 7y j pierces through a cubic Gaussian surface of edge length…
A: Electric flux
Q: A flat sheet is in the shape of a rectangle with sides of lengths 0.400 m and 0.600 m. The sheet is…
A: Given Length l = 0.400 m breadth b = 0.600 m Electric field E = 95.0 N/C Angle θ…
Q: A 44.0-cm-diameter circular loop is rotated in a uniform electric field until the position of…
A: We know, Electric flux is given as, ϕ=E→.A→=EAcosθ where θ is the angle between E and A Now flux…
Q: Assume the magnitude of the electric field on each face of the cube of edge L = 1.10 m in the figure…
A: Given that:- Edge length of cube=L=1.1m
Q: A cube with 1.40 m edges is oriented as shown in the figure in a region of uniform electric field.…
A:
A cone is resting on a tabletop as shown in the figure with its face horizontal.
A uniform electric field of magnitude 4550 N/C points horizontally to the right.
How much electric flux passes through the sloping side surface area of the cone?
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
- A vertical electric field of magnitude 2.00 x 104 N/C exists above the Earth's surface on a day when a thunderstorm is brewing. A car with a rectangular size of 6.00 m by 3.00 m is traveling along a dry gravel roadway sloping downward at 10.0°. Determine the electric flux through the bottom of the car.There is an electric flux of 22.5 N-m²/C through the square region shown in the figure. Each side of the square has a length of 0.100 m, it is the unit vector normal to the plane of the surface, and the electric field is at an angle of 0 101.0 relative to the plane of the surface. Assuming that the field is uniform over the region shown, what is the magnitude E of the electric field? E= 1.179 x104 Incorrect N/CA 40.0-cm-diameter circular loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 5.20 x 105 Nm²/C. What is the magnitude of the electric field?
- P10A closed surface with dimensions a=b%3D0.40 m and c30.60 m is located as in the figure below. The left edge of the closed surface is located at position x= a. The electric field in the region is non-uniform and is given by E=(3.0+ 46x² ) i N/C, where x is in meters. Calculate the net electric flux leaving the closed surface? x= a Select one: OA 15.38 OB. 4.42 OC 6.18 OD. 147 OE 10.78 9:03 PM 4/30/2021A flat sheet is in the shape of a rectangle with sides of lengths 0.400 m and 0.600 m. The sheet is immersed in a uniform electric field of magnitude 55.0 N/C that is directed at 20 degrees from the plane of the sheet (Figure 1). Find the magnitude of the electric flux through the sheet. Express your answer with the appropriate units.
- The figure below shows a solid conducting sphere with radius R = 7.00 cm. Upon inspection, the electric field at a distance r = 9.00 cm from the center of the conducting sphere is +250. kN/C. What is the surface charge density of the conducting sphere? (eno = 8.854 x 10-12 C²/N-m2) -R- +3.66 HC m2 nC +3.66 m2 nC +1.34 +1.34 m2 O none of the given choicesA electric field at 3.8 cm from the centre of a long copper rod of radius 0.7 cm has a magnitude 3.6 N/C and is directed outward from the axis of the rod. Part 1 What is the charge per unit length of the copper rod? = number (rtol=0.03, atol=0) C/m Part 2 What would be the electric flux through a cube of side 8.0 cm situated such that the rod passes through the opposite sides of the cube perpendicularly? number (rtol=0.03, atol=0) Nm?/CConsider a closed triangular box resting within a horizontal electric field of magnitude E = 7.80×104 N/C as shown in the following figure. Calculate the electric flux through (a) the vertical rectangular surface (the 10 cm × 30 cm surface), (b) the slanted surface, and (c) the entire surface of the box. 10.0 cm 30.0 cm 60.0°
- A flat sheet is in the shape of a rectangle with sides of lengths 0.400 m and 0.600 m. The sheet is immersed in a uniform electric field of magnitude 90.0 N>C that is directed at 20° from the plane of the sheet. Find the magnitude of the electric flux through the sheet.Consider a closed triangular box resting within a horizontal electric field of magnitude E = 8.26 104 N/C as shown in the figure below. (a) Calculate the electric flux through the vertical rectangular surface of the box.30° y a An object having the shape of a rectangular prism is placed in a uniform electric field with constant magnitude (E) coming to the top surface by passing through yz plane as shown in the figure. As shown in the figure, the electric field has an angle of 30° to the normal of the top surface. What is the total electric flux in terms of Nm2/C through the bottom and back surfaces? (E=50 N/C; a=lm; b32m; c=3m). a) 639.23 b)- 148.2 c)- 107.179 d)- 20.1 e) 19.615 C.