A 96 cm diameter loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 3.1 x 10 N m/C. What is the electric field strength? Answer in units of N/C.
A 96 cm diameter loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 3.1 x 10 N m/C. What is the electric field strength? Answer in units of N/C.
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter23: Electric Fields
Section: Chapter Questions
Problem 23.86CP: Consider the charge distribution shown in Figure P23.85. (a) Show that the magnitude of the electric...
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E = flux /A
d= 96cm
A= π r2 = 0.7238 m2
Flux = 3.1 × 105 Nm2/C
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