A 96 cm diameter loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 3.1 x 10 N m/C. What is the electric field strength? Answer in units of N/C.

Physics for Scientists and Engineers, Technology Update (No access codes included)
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ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter23: Electric Fields
Section: Chapter Questions
Problem 23.86CP: Consider the charge distribution shown in Figure P23.85. (a) Show that the magnitude of the electric...
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A 96 cm diameter loop is rotated in a uniform
electric field until the position of maximum
electric flux is found. The flux in this position
is measured to be 3.1 x 10° N m/C.
What is the electric field strength?
Answer in units of N/C.
Transcribed Image Text:A 96 cm diameter loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 3.1 x 10° N m/C. What is the electric field strength? Answer in units of N/C.
Expert Solution
Step 1

E = flux /A 

d= 96cm 

A= π r = 0.7238 m2 

Flux = 3.1 × 105 Nm2/C 

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