A 96 cm diameter loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 3.1 x 10 N m/C. What is the electric field strength? Answer in units of N/C.
A 96 cm diameter loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 3.1 x 10 N m/C. What is the electric field strength? Answer in units of N/C.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:A 96 cm diameter loop is rotated in a uniform
electric field until the position of maximum
electric flux is found. The flux in this position
is measured to be 3.1 x 10° N m/C.
What is the electric field strength?
Answer in units of N/C.
Expert Solution

Step 1
E = flux /A
d= 96cm
A= π r2 = 0.7238 m2
Flux = 3.1 × 105 Nm2/C
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