A company has five branches and want to test if the mean employee's salaries are equal. A sample of 3 employees from each location was selected. You are given the ANOVA table below: Source of Sum of squares Degrees of Мean F variation freedom square Treatments 36,648 9,162 Y Error A C Total 57,095 D Using the critical value approach what is your conclusion at the %5 significance level (E. =3.48) : Select one: O a. F = 4.48 and we fail to reject the null hypothesis O b. F= 2.50 and we fail to reject the null hypothesis n c.F = 4.48 and we reject the null hypothesis O d. F = 2.50 and reject the null hypothesis A O Ps Lr JUN étv 12
A company has five branches and want to test if the mean employee's salaries are equal. A sample of 3 employees from each location was selected. You are given the ANOVA table below: Source of Sum of squares Degrees of Мean F variation freedom square Treatments 36,648 9,162 Y Error A C Total 57,095 D Using the critical value approach what is your conclusion at the %5 significance level (E. =3.48) : Select one: O a. F = 4.48 and we fail to reject the null hypothesis O b. F= 2.50 and we fail to reject the null hypothesis n c.F = 4.48 and we reject the null hypothesis O d. F = 2.50 and reject the null hypothesis A O Ps Lr JUN étv 12
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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