A company has five branches and want to test if the mean employee's salaries are equal. A sample o 3 employees from each location was selected. You are given the ANOVA table below: Source of Sum of squares Degrees of Mean F variation freedom square Treatments 36,648 9,162 Y Error A Total 57,095 Find the degrees of freedom for the treatments, error and total variations Select one: O a. B = 5, C = 15, D = 20 O b. B = 4, C = 15, D = 19 O C.B = 5, C = 10, D = 15 Od. B= 4,C = 10, D = 14 JUN

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A company has five branches and want to test if the mean employee's salaries are equal. A sample of
3 employees from each location was selected. You are given the ANOVA table below:
Source of
Sum of squares
Degrees of
Мean
F
variation
freedom
square
Treatments
36,648
9,162
Y
Error
Total
57,095
Find the degrees of freedom for the treatments, error and total variations
Select one:
O a. B = 5,C = 15, D= 20
O b. B = 4, C = 15, D = 19
OC.B = 5, C = 10, D= 15
Od. B= 4, C = 10, D = 14
JUN
12
stv
Transcribed Image Text:A company has five branches and want to test if the mean employee's salaries are equal. A sample of 3 employees from each location was selected. You are given the ANOVA table below: Source of Sum of squares Degrees of Мean F variation freedom square Treatments 36,648 9,162 Y Error Total 57,095 Find the degrees of freedom for the treatments, error and total variations Select one: O a. B = 5,C = 15, D= 20 O b. B = 4, C = 15, D = 19 OC.B = 5, C = 10, D= 15 Od. B= 4, C = 10, D = 14 JUN 12 stv
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