A colored dye compound decomposes to give a colorless product. The original dye absorbs at 608 nm and has an extinction coefficient of 4.7 x 104 M¹cm¹ at that wave- length. You perform the decomposition reaction in a 1-cm cuvette in a spectrometer and obtain the following data: Time (min) 0 30 60 90 120 Absorbance at 608 nm - 1.254 '0.941 0.752 0.672 0.545 From these data, determine the rate law for the reaction "dye → product" and determine the rate constant.

A colored dye compound decomposes to give a colorless product. The original dye absorbs at 608 nm and has an extinction coefficient of 4.7 x 104 M¹cm¹ at that wave- length. You perform the decomposition reaction in a 1-cm cuvette in a spectrometer and obtain the following data: Time (min) 0 30 60 90 120 Absorbance at 608 nm - 1.254 '0.941 0.752 0.672 0.545 From these data, determine the rate law for the reaction "dye → product" and determine the rate constant.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

A colored dye compound decomposes to give a colorless
product. The original dye absorbs at 608 nm and has an
extinction coefficient of 4.7 X 104 M¹cm¹ at that wave-
length. You perform the decomposition reaction in a 1-cm
cuvette in a spectrometer and obtain the following data:
Time (min)
0
30
60
90
120
Absorbance at 608 nm
1.254
'0.941
0.752
0.672
0.545
From these data, determine the rate law for the reaction
"dye - product" and determine the rate constant.

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Step 1: Beer’s lambert law!

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Step 2: Calculation for molar concentration at absorbance value of 1.254

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Step 3: Finding out the concentration related to each absorbance value!

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Step 4: Finding out the order of reaction!

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Step 5: Finding out the rate law

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Step 6: Finding out the value of rate constant!

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