We typically don't have a value for the frequency factor, A, so we can be creative to determine the activation energy using the two-point method. (This is similar to how we applied the Clausius-Clapeyron equation!) The frequency factor does not depend on temperature, so it will remain constant, as will the activation energy, Ea. Ea (元) In k₂ = In A - Ea B (1) In k₁ = In A Using the equations above, determine an equation for Inby solving both equations above equal for In A and then setting them equal to each other. (check your result with me or one of the

We typically don't have a value for the frequency factor, A, so we can be creative to determine the activation energy using the two-point method. (This is similar to how we applied the Clausius-Clapeyron equation!) The frequency factor does not depend on temperature, so it will remain constant, as will the activation energy, Ea. Ea (元) In k₂ = In A - Ea B (1) In k₁ = In A Using the equations above, determine an equation for Inby solving both equations above equal for In A and then setting them equal to each other. (check your result with me or one of the

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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In k -7.5 -8.0 -8.5 -9.0 3.10 3.15 3.20 3.25 3.30 3.35 1/Tx 10³ (K-¹) 88.9 kJ/mol 3.32 x 104 kJ/mol There is insufficient information to determine the activation energy 8.31 kJ/mol 130 kJ/mol
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