A coffee cup calorimeter contains 156.56 g of water at 22.50 °C. A 66.065 g piece of iron is heated to 101.17 °C. The piece of iron is added to the coffee cup caloriemter and the contents reach thermal equilibrium at 25.68 °C. The specific heat capacity of iron is 0.449 and the -pecific heat capacity of water is 4.184 How much heat, q, is lost by the piece of iron? Firon = How much heat, q, is gained by the water? qwater = Ccalorimeter = J The difference between the heat lost by the piece of iron and the heat gained by the water is due to heat transfer to the styrofoam and the heat required to raise the temperature of the calorimeter. What is the heat capacity of the styrofoam calorimeter in joules per kelvin ()? What would be the final temperature of the system if all of the heat lost by the iron was absorbed by the water? J
A coffee cup calorimeter contains 156.56 g of water at 22.50 °C. A 66.065 g piece of iron is heated to 101.17 °C. The piece of iron is added to the coffee cup caloriemter and the contents reach thermal equilibrium at 25.68 °C. The specific heat capacity of iron is 0.449 and the -pecific heat capacity of water is 4.184 How much heat, q, is lost by the piece of iron? Firon = How much heat, q, is gained by the water? qwater = Ccalorimeter = J The difference between the heat lost by the piece of iron and the heat gained by the water is due to heat transfer to the styrofoam and the heat required to raise the temperature of the calorimeter. What is the heat capacity of the styrofoam calorimeter in joules per kelvin ()? What would be the final temperature of the system if all of the heat lost by the iron was absorbed by the water? J
Chemistry for Engineering Students
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Chapter9: Energy And Chemistry
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Problem 9.104PAE: 9.104 An engineer is using sodium metal as a cooling agent in a design because it has useful thermal...
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![A coffee cup calorimeter contains 156.56 g of water at 22.50 °C. A 66.065 g piece of iron is
heated to 101.17 °C. The piece of iron is added to the coffee cup caloriemter and the contents
reach thermal equilibrium at 25.68 °C. The specific heat capacity of iron is 0.449 and the
specific heat capacity of water is 4.184
How much heat, q, is lost by the piece of iron?
Fire =
How much heat, q, is gained by the water?
qwater =
Ccalorimeter =
The difference between the heat lost by the piece of iron and the heat gained by the water is due to heat transfer to the styrofoam
and the heat required to raise the temperature of the calorimeter. What is the heat capacity of the styrofoam calorimeter in joules
per kelvin (*)?
What would be the final temperature of the system if all of the heat lost by the iron was absorbed by the water?
Tinal
J
=
J
°C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F34672991-aec6-46ee-ad36-157c83d795dd%2Fc467aa41-4057-413a-92c8-84c2c70fd603%2Fezsuwg9_processed.png&w=3840&q=75)
Transcribed Image Text:A coffee cup calorimeter contains 156.56 g of water at 22.50 °C. A 66.065 g piece of iron is
heated to 101.17 °C. The piece of iron is added to the coffee cup caloriemter and the contents
reach thermal equilibrium at 25.68 °C. The specific heat capacity of iron is 0.449 and the
specific heat capacity of water is 4.184
How much heat, q, is lost by the piece of iron?
Fire =
How much heat, q, is gained by the water?
qwater =
Ccalorimeter =
The difference between the heat lost by the piece of iron and the heat gained by the water is due to heat transfer to the styrofoam
and the heat required to raise the temperature of the calorimeter. What is the heat capacity of the styrofoam calorimeter in joules
per kelvin (*)?
What would be the final temperature of the system if all of the heat lost by the iron was absorbed by the water?
Tinal
J
=
J
°C
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