A 1095 g piece of iron initially at 1371 °C is submerged in 1000.0 g of water initially at 20.0 °C. The temperature of the water increases, and some of the water evaporates. At thermal equilibrium, the final temperature of the iron, water, and water vapor (steam) is 100.0 °C. How many moles of water evaporated to reach thermal equilibrium?

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Chapter7: Chemical Energy
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A 1095 g piece of iron initially at 1371 °C is submerged in 1000.0 g of water
initially at 20.0 °C. The temperature of the water increases, and some of the
water evaporates. At thermal equilibrium, the final temperature of the iron,
water, and water vapor (steam) is 100.0 °C. How many moles of water
evaporated to reach thermal equilibrium?
The specific heat capacity of iron is Cs, Fe = 0.449 J /g.°C
The specific heat capacity of liquid water is Cs, water = 4.18 J/g.°C
The enthalpy of vaporization of water is AHvap
:40.7 kJ/mol
Circle your answer on the written template. Be sure that it is in the correct units
(mol) and has the correct number of significant figures.
Transcribed Image Text:A 1095 g piece of iron initially at 1371 °C is submerged in 1000.0 g of water initially at 20.0 °C. The temperature of the water increases, and some of the water evaporates. At thermal equilibrium, the final temperature of the iron, water, and water vapor (steam) is 100.0 °C. How many moles of water evaporated to reach thermal equilibrium? The specific heat capacity of iron is Cs, Fe = 0.449 J /g.°C The specific heat capacity of liquid water is Cs, water = 4.18 J/g.°C The enthalpy of vaporization of water is AHvap :40.7 kJ/mol Circle your answer on the written template. Be sure that it is in the correct units (mol) and has the correct number of significant figures.
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