A circular footing with a 1.5 m diameter is to be constructed 1.2 m below the ground surface. The subsoil consists of a uniform deposit of dense soil having the following strength parameters. Angle of internal friction = 25o , Nc = 24.1 ; Nq =13.1 ; N = 9.1 Unconfined compressive strength = 96 kN/m2 Unit weight of soil = 20.12 kN/m3 The ground water table is at great depth and its effect can be ignored. a) Compute the Ultimate bearing capacity of the soil. b) Compute the gross allowable bearing capacity of the soil using a factor of safety of 3. c) Compute the allowable load the footing could carry
A circular footing with a 1.5 m diameter is to be constructed 1.2 m below the ground surface. The subsoil consists of a uniform deposit of dense soil having the following strength parameters. Angle of internal friction = 25o , Nc = 24.1 ; Nq =13.1 ; N = 9.1 Unconfined compressive strength = 96 kN/m2 Unit weight of soil = 20.12 kN/m3 The ground water table is at great depth and its effect can be ignored. a) Compute the Ultimate bearing capacity of the soil. b) Compute the gross allowable bearing capacity of the soil using a factor of safety of 3. c) Compute the allowable load the footing could carry
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A circular footing with a 1.5 m diameter is to be constructed 1.2 m below the ground surface. The
subsoil consists of a uniform deposit of dense soil having the following strength parameters.
Angle of internal friction = 25o
, Nc = 24.1 ; Nq =13.1 ; N = 9.1
Unconfined compressive strength = 96 kN/m2
Unit weight of soil = 20.12 kN/m3
The ground water table is at great depth and its effect can be ignored.
a) Compute the Ultimate bearing capacity of the soil.
b) Compute the gross allowable bearing capacity of the soil using a factor of safety of 3.
c) Compute the allowable load the footing could carry
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