Hope your help foundation question (CEE430) thanks
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Hope your help foundation question (CEE430) thanks

Transcribed Image Text:**Problem Statement:**
A 4 m x 8 m rectangular footing will be placed on the ground surface as shown in the figure. The total load acting on the footing will be 900 kN. Determine the consolidation settlement of the foundation. Assume the clay layer is normally consolidated with \(C_c = 0.3\) and use the 2:1 method to calculate the stress increase at the middle of the clay layer.
**Diagram Explanation:**
The diagram illustrates a cross-section of the soil layers beneath the proposed footing:
- **Sand Layer:**
- Two layers of sand are shown.
- The first sand layer is 2.8 m thick with a dry unit weight \(\gamma_{\text{dry}} = 18.0 \text{kN/m}^3\).
- The second sand layer is 4.2 m thick and has a wet unit weight \(\gamma_{\text{wet}} = 18.6 \text{kN/m}^3\).
- **Clay Layer:**
- This layer is situated below the sand, with a thickness of 3.0 m.
- Relevant properties provided include:
- Wet unit weight \(\gamma_{\text{wet}} = 18.2 \text{kN/m}^3\)
- Initial void ratio \(e_0 = 0.82\)
- Plastic Limit \(\text{PL} = 20\)
- Liquid Limit \(\text{LL} = 44\)
- **Water Table (W.T.):**
- Positioned at the interface between the upper sand layer and the clay layer.
**Objective:**
Calculate the consolidation settlement utilizing the change in stress at the center of the clay layer, which can be derived using the 2:1 stress distribution method.
Expert Solution

Step 1
Effective stress at the center of the clay layer, = ϒd 2.8 + (ϒsat- ϒw)4.2 + (ϒsat clay – ϒw)1.5
= 18 2.8 + (18.6- 9.81)4.2 + (18.2– 9.81)1.5
= 50.4 + 36.918 + 12 .585
= 99.903 kN/m2
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