Using terzaghi Problem No. 2 A circular footing with 1.50m diameter is to be constructed 1.22m below the ground surface. The subsoil consists of a uniform deposit of dense soil having the following strength parameters. The ground water table is at great depth and its effect can be ignored. Angel of Internal Friction = 25.00⁰ Unconfined compressive strength = 96 kN/m3 Unit weight of Soil = 201.12 kN/m3 a) Compute the ultimate bearing capacity of the soil using vesic equation. uy compute the gross allowable bearing capacity of the soil using a factor of safety of 3.00 c) Compute the total allowable load that the footing can carry.

Q: For general c-o soil, cohesion c is 50 kPa, the total unit weight y, is 20 kN/m3 and the bearing…

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Q: A footing with 2x5 m is founded at a depth of 1 m in a stiff clay of saturated unit weight 19 kN/m³,…

A: Saturated unit weight= 19 KN/m3  Depth of footing= 1 m  Su= 105 Kpa Footing = 2*5 m

Q: Ex1: A footing is uniformly loaded with q= 100 kN/m¹ as shown in the figure. Compute the vertical…

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Q: The 2.5 m x 3.5 m rectangular spread footing placed at a depth of 1.5 m supports a vertical load of…

A: To find:Factor of safety

Q: bearing capacity for hansen method

A:

Q: A square footing 2.5m x 2.5m is shown in the figure below. Determine the magnitude of the safe gross…

A: Given that :-Square Footing = 2.5 m  2.5 m  = 15 c = 0ϕ =  = 19 = 9.19 = 2 m  = 1 mF.O.S = 3Required…

Q: A rectangular foundation has dimensions B = 8’, L = 10’, D = 3’.  It is underlain by a medium dense…

A: B=8' L=10' D=3' Es= 300ksf γ= 120pcf ∆p= 2tsf Foundation- rectangular Soil- medium dense sand To…

Q: Y-17 kN/m d-36° c'-10 kN/m? Df=1.5m B=1.25m The above figure shows a square footing. The properties…

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Q: . If the footing shown below is not to settle more than 1 in., what is the maximum load it can…

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Q: A 5-ft wide, 8-ft long, 3-ft deep footing supports a downward load of 200k and a horizontal shear…

A: Given wide = 5ft ; long =8ft ; deep =3ft Downward load = 200000 ; Horizontal shear load =25000

Q: A footing with 2×5 m is founded at a depth of 1 m in a stiff clay of saturated unit weight 19 kN/m³,…

A: Saturated unit weight= 19 KN/m3  Depth of footing= 1 m

Q: b. Ultimate soil bearing capacity, qu (in kN/m2) qu = c. Allowable soil bearing capacity, qall (in…

A: γ = 17 Knm3ϕ = 36°c' = 10 KNm2Df = 1.5mB = 1.25m

Q: Two parallel strip footings 3m wide and 5m apart(measured from centre to centre), which transmit a…

A: For strip footing generally load distribution is taken as 1 V: 0.5 H increment  of total vertical…

Q: A square footing is proposed to be constructed on the silty sand layer as shown in Figur Q2. If the…

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Q: 2. A circular footing having a diameter of 2m has its bottom at a depth of 2.5m from the ground…

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Q: The allowable settlement for the shown square footing is 2.5 cm. the footing is placed on clay soil…

A: Data given Find : Consolidation settlement

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.