O Part 4: Directional relationship between velocity & magnetic forceA charged particle is moving through a B-field and experiences a magnetic force (FB>0). The magnetic force vector is shown below. Choose allthe vectors that could represent the velocity.MagneticVelocity of charged particleforce80°So80°80°O Part 5: Directional relationship between current & B-fieldA current-carrying wire is in a B-field and experiences a magnetic force (FB>0). The B-field vector is shown below. Choose all the arrows thatcould represent the current direction.B-fieldCurrent direction80°306060°30°40*30°40...

Given The force acting 10obelow the horizontal

A charged particle is moving through a B-field and experiences a magnetic force (Fg>0). The magnetic force vector is shown below. Choose all the vectors that could represent the velocity. Magnetic force Velocity of charged particle So 80 80 80° 4..........

A charged particle is moving through a B-field and experiences a magnetic force (Fg>0). The magnetic force vector is shown below. Choose all the vectors that could represent the velocity. Magnetic force Velocity of charged particle So 80 80 80° 4..........

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A particle of mass m carrying a negative charge q passes through a perpendicular magnetic field B al speed v. as shown below. The radius of its circular path while it is within the magnetic field is r. (see diagram) Which of the following is equal to the speed, r. of the particle? A) qr/mB B) qBr/m C) qB/rm D) m/qBr
A current-carrying wire is in a B-field and experiences a magnetic force (FB>0). The magnetic force vector is shown below. Choose all the arrows that could represent the current direction. Magnetic force Current direction 45° 45° 45* 45° 45° 40 45° 45°
In vacuum, magnetic force on a moving charged particle provides an acceleration to the particle. Thus, it also changes the kinetic energy of the particle. O True O False The direction of magnetic force is perpendicular both to the velocity of the particle and to the magnetic field. True O False The net magnetic force acting on any closed current-carrying loop in a uniform magnetic field is zero. True O False All electric field lines are continuous and always form closed loops. OTrue False
A particle with unknown properties moves into a region of space containing both a uniform electric field and a uniform magnetic field, as shown below. The particle begins to deviate upwards from its original trajectory. How do the magnitudes of the two forces compare? OB The electric force is stronger than the magnetic force The magnetic force is stronger than the electric force А. В. С. The electric force and the magnetic forceare equal in magnitude (but nonzero) The electric force and the magnetic force are both exactly zero Nothing can be determined without additional information D. Е.
Question 5
QUESTION 6 Two long current carrying wires, I and I2, are separated by 2 mm and both carry a current of 8 A. What is the x-component of the magnetic force in newtons on a one meter length of one of the top wire?
A proton is moving to the right above a horizontal wire that carries a current to the right. What is the direction of the magnetic force on the proton?
Can you answer problem 4? Can you also provide a short explanation for the answer you chose?
Two particles have the same charge (q1=q23D1.6x10-1C) and different masses undergo circular motion in a constant magnetic field (B = 0.40 T) with the same speed of 5x10° m/s. If their circular paths differ in radius by 4.9 cm, what is the difference in the mass of these two particles? m2 ml a. 8.18 x10^(-28) kg O b. 7.11 x10^(-28) kg Oc 6.27 x10^(-28) kg O d. 5.00 x10^(-28) kg O e. 9.21 x10^(-28) kg G-Guard O O
When a charged particle moves perpendicularly to the direction of a uniform magnetic field, the direction of the magnetic force is perpendicular to both the direction of the magnetic field and the direction of the velocity of the charged particle. Accordingly, the charge begins to move in a circular path. Since the direction of the magnetic force is toward the center of the circular path the charged particle moves along, the magnetic force is a centripetal force (recall centripetal forces from chapter 5 of the text, covered in PHY 2010). A schematic of such motion is shown below. The "X"s represent the magnetic field that is directed into the plane of this screen. The direction of velocity and magnetic force lie within the plane of this screen and are at right angles to one another, as shown below. If a charge of magnitude 7.45x10-17C, with speed 4.66x106 m/s, and mass 7.12x10-25kg moves within the magnetic field of magnitude 3.96x10-2T, what is the resulting radius of the path…
What is the magnitude of the magnetic force on a charged particle (Q = 5.0 μC) moving with a speed of 80 km/s in the positive x direction at a point where B₂ = 3.0 T? a. b. C. d. e. 2.8 N 1.6 N 1.2 N 2.0 N 0.4 N