**Question:**What is the magnitude of the magnetic force on a charged particle \((Q = 5.0 \, \mu C)\) moving with a speed of 80 km/s in the positive \(x\) direction at a point where \(B_z = 3.0 \, T\)?**Options:**a. 2.8 N b. 1.6 N c. 1.2 N d. 2.0 N e. 0.4 N **Explanation:**To solve this problem, we apply the formula for magnetic force acting on a charged particle in a magnetic field: \[ F = Q \cdot v \cdot B \cdot \sin(\theta) \]Where: - \( F \) is the magnetic force. - \( Q \) is the charge of the particle = \(5.0 \, \mu C = 5.0 \times 10^{-6} \, C\). - \( v \) is the speed of the particle = 80 km/s = 80,000 m/s.- \( B \) is the magnetic field = 3.0 T.- \(\theta\) is the angle between velocity and the magnetic field direction. Here, the velocity is in the \(x\) direction and magnetic field \(B_z\) is in the \(z\) direction, so \(\theta = 90^\circ\) and \(\sin(90^\circ) = 1\).Plugging in the values:\[ F = 5.0 \times 10^{-6} \times 80,000 \times 3.0 \times 1 = 1.2 \, \text{N} \]Therefore, the correct answer is **c. 1.2 N**.

Given data: Charge (Q) = 5.0 μC = 5.0×10-6 C Velocity (v) = 80 km/s, in positive x-direction…

What is the magnitude of the magnetic force on a charged particle (Q = 5.0 µC) moving with a speed of 80 km/s in the positive x direction at a point where B₂ = 3.0 T? a. b. C. d. e. 2.8 N 1.6 N 1.2 N 2.0 N 0.4 N

What is the magnitude of the magnetic force on a charged particle (Q = 5.0 µC) moving with a speed of 80 km/s in the positive x direction at a point where B₂ = 3.0 T? a. b. C. d. e. 2.8 N 1.6 N 1.2 N 2.0 N 0.4 N

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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