A charged particle moves in a region of uniform magnetic field along a helical path (radius= 5.0 cm, pitch = 12 cm, period = 27.6 ms). What is the speed of this particle? ooo ² topl Pitch -2r- B B
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Q: Part B A particle with charge magnetic field B=-(1.26 T )k. The magnetic force on the 5.10 nC is…
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Q: 2: A wire of length L= 0.65 m and mass m = 0.095 kg carries a current of I= 0.75 A. The wire is…
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Q: A particle with charge – 5.10 nC is moving in a uniform magnetic field B = -( 1.30 T )k. The…
A: Given: The charge on the particle is -5.1 nC. B→=-1.3 Tk^F→=-3.1×10-7 Ni^+7.6×10-7 Nj^
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A: Answer 1) The Correct option is C. When the electrons are discharged from an electron gun, their…
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A: Given data: Charge (q) = 2.0 μC = 2.0×10-6 C Speed (v) = 6.0×106 m/s Magnetic field (B) = 0.30 T…
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A: GivenB=0.75 Tm=6.58×10-27 kgqe=1.602×10-19 C
Q: A particle with charge - 5.80 nC is moving in a uniform magnetic field B = −( 1.27 T)k. The magnetic…
A: Solution:-Given thatq=-5.80 nC=-5.8×10-9 CB→=-(1.27)k^ TF→=[-(3×10-7)i^+(7.6×10-7) j^] N
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A: Note:- A charged particle travelling at right angles to a magnetic field undergoes helical motion,…
Q: A proton moves with a velocity of V = (51-5j + k) m/s in a region in which the magnetic field is B =…
A: The velocity of the proton is v=5i-5j+k m/s. The magnetic field is B=i+2j-k T.
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Q: Needs Complete solution with 100 % accuracy don't use chat gpt or ai plz plz plz.
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Q: b) What is the y component of this force? O 67.1 N 53.6 N O41.9 11.1 N
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Q: A particle with mass 1.67x10-3 kg and charge of +1.32x10 C has, at a given instant, a velocity of…
A: Given:B=1.19 T Mass, m=1.67×10-3 kg Charge, q=1.32×10-8 C Velocity, v=2.90×104 m/s Magnetic field,…
Q: Problem 14: A proton is traveling with a velocity of V = Vxit vyj, where vx = 93 m/s and vy = 49…
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- A 68.0-cm-diameter cyclotron uses a 450 V oscillating potential difference between the dees. Part A What is the maximum kinetic energy of a proton if the magnetic field strength is 0.740 T? Express your answer with the appropriate units. Value Submit Part B μA Submit Units Request Answer IV—| ΑΣΦ 3 How many revolutions does the proton make before leaving the cyclotron? ? Request Answer ?An iron (density ρ) rod with length L, cross sectional area A, spans across two parallel, metal train tracks. The tracks are connected to a power supply and have a potential ∆V across them. Between the tracks are placed magnets such that the B-field points directly upwards with strength B. What is the acceleration of the iron rod be the moment it starts from rest? What will acceleration be as a function of speed as it continues? Assume the contact is frictionless between the tracks and the rod so that no force of friction needs to be overcome. What will the top speed of the rod be under these conditions?Part D A particle with charge – 5.10 nC is moving in a uniform magnetic field B= -(1.26 T )k. The magnetic force on the particle is measured to be Calculate the scalar product v· F. Assume the velocity has only components found in the previous parts. F = -( 3.10x10-7 N )ê+(7.60x10-7 N )3. Express your answer in meters per second times newtons. Nνα ΑΣφ ? m/s N Submit Request Answer Part E What is the angle between v and F? Give your answer in degrees. Express your answer in degrees. ? = Submit Request Answer Provide Feedback
- ▸ Part A What value of magnetic field would make a beam of electrons, traveling to the right at a speed of 5.4×100 m/s. go undeflected through a region where there is a uniform electric field of 9400 V/m pointing vertically up? Express your answer to two significant figures and include the appropriate units. B = 1.7x10-3 T Submit ✓ Correct Part B Previous Answers Part C What is the frequency of the circular orbit of the electrons if the electric field is turned off? Express your answer to two significant figures and include the appropriate units. HA f- Value Submit Request Answer Units ?A charged particle moves through a velocity selector at constant velocity. The velocity selector is configured with "crossed" electric and magnetic fields of magnitude E = 1.50 x 104 N/C and B = 0.4 T. %3D Hint a. What is the velocity of the charged particle? Velocity of the charged particle is x 104 m/s. b. When the electric field is turned off, the charged particle travels in a circular path of radius 6 mm, as it travels through the magnetic field (still at B = 0.4 T). What is the mass-to-charge ratio of the particle? Hint for (b) Mass-to-charge ratio of the part is kg/C. (Use the "E" notation to enter your answer in scientific notation. For example, to enter 3.14 × 10´ 12".) - 12 enter "3.14E-R A single wire is formed into circular loop of radius 14.0 cm is carrying a current of 11= 2.98 amps. The wire loop is placed so that the center of the loop is a distance y cm away from a long straight wire carrying current l2= 6.00 amps. If the strength of the magnetic field in the center of the loop is zero, what is the distance y? y = cm
- A bar magnet is attached solidly to a frictionless surface and its length is aligned with the x axis. To the right of the first magnet a short distance away is a second bar magnet with its center placed on the x axis and its length perpendicular to the x axis. The second magnet is free to move. Once placed in position at rest, which best describes the initial motion of the second magnet? O The magnet will move away from the fixed magnet. The magnet will not move. The magnet will start to rotate. O The magnet will move toward the fixed magnet.A 2.0 µC positive charge of speed 6.0 × 106 m/s is moving in a 0.30 T magnetic field, the magnetic field and the charge's velocity are in the same direction as shown. What is the magnitude of the magnetic force on the charge, in Newtons? Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement. B +Chapter 28, Problem 020 An electron is accelerated from rest through potential difference V and then enters a region of uniform magnetic field, where it undergoes uniform circular motion. The figure gives the radius r of that motion versus V¹/2. The vertical axis scale is set by rs= 4.0 mm, and the horizontal axis scale is set by V¹/2= 32.9 V¹/2. What is the magnitude of the magnetic field? r (mm) VI/2 V¹/2 (¹/2)