constant velocity. The velocity selector is configured with "crossed" electric and magnetic fields of magnitude E = 1.50 × 10² N/C and B = 0.4 T. Hint a. What is the velocity of the charged particle? Velocity of the charged particle is 104 m/s. S. b. When the electric field is turned off, the charged particle travels in a circular path of radius 6 mm, as it travels through the magnetic field (still at B = 0.4 T). What is the mass-to-charge ratio of the particle? Hint for (b)
constant velocity. The velocity selector is configured with "crossed" electric and magnetic fields of magnitude E = 1.50 × 10² N/C and B = 0.4 T. Hint a. What is the velocity of the charged particle? Velocity of the charged particle is 104 m/s. S. b. When the electric field is turned off, the charged particle travels in a circular path of radius 6 mm, as it travels through the magnetic field (still at B = 0.4 T). What is the mass-to-charge ratio of the particle? Hint for (b)
College Physics
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Chapter1: Units, Trigonometry. And Vectors
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![### Educational Content: Velocity Selector and Charged Particles
A charged particle moves through a velocity selector at constant velocity. The velocity selector is configured with "crossed" electric and magnetic fields of magnitude:
- \( E = 1.50 \times 10^4 \, \text{N/C} \)
- \( B = 0.4 \, \text{T} \)
#### Problem Statement
**a.** What is the velocity of the charged particle?
- **Solution:**
- Velocity of the charged particle is \([ \, ] \times 10^4 \, \text{m/s} \).
**b.** When the electric field is turned off, the charged particle travels in a circular path of radius 6 mm, as it travels through the magnetic field (still at \( B = 0.4 \, \text{T} \)). What is the mass-to-charge ratio of the particle?
- **Solution:**
- Mass-to-charge ratio of the particle is \([ \, ] \, \text{kg/C} \). (Use the "E" notation to enter your answer in scientific notation. For example, to enter \( 3.14 \times 10^{-12} \), enter "3.14E-12".)
### Explanation of Concepts
1. **Velocity Selector:**
- A device that uses perpendicular electric and magnetic fields to separate particles based on their velocities. The fields exert forces that can balance each other, allowing only particles with a specific velocity to pass through undeflected.
2. **Circular Motion in a Magnetic Field:**
- When the electric field is removed, charged particles move in a circular path due to the magnetic force. The radius of the path helps determine properties such as the mass-to-charge ratio.
### Hints
- For part (a), use the principle that electric ( \( E \) ) and magnetic ( \( B \) ) forces balance each other: \( qE = qvB \), leading to \( v = \frac{E}{B} \).
- For part (b), use the relationship for circular motion: \( qvB = \frac{mv^2}{r} \), to find the mass-to-charge ratio. Here, \( r \) is the radius of the circle.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe09d4462-f34d-4530-ac40-5ce52271c7b7%2Feef4af95-678f-4d20-82a8-3e2744f55f66%2F11wnu3k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Educational Content: Velocity Selector and Charged Particles
A charged particle moves through a velocity selector at constant velocity. The velocity selector is configured with "crossed" electric and magnetic fields of magnitude:
- \( E = 1.50 \times 10^4 \, \text{N/C} \)
- \( B = 0.4 \, \text{T} \)
#### Problem Statement
**a.** What is the velocity of the charged particle?
- **Solution:**
- Velocity of the charged particle is \([ \, ] \times 10^4 \, \text{m/s} \).
**b.** When the electric field is turned off, the charged particle travels in a circular path of radius 6 mm, as it travels through the magnetic field (still at \( B = 0.4 \, \text{T} \)). What is the mass-to-charge ratio of the particle?
- **Solution:**
- Mass-to-charge ratio of the particle is \([ \, ] \, \text{kg/C} \). (Use the "E" notation to enter your answer in scientific notation. For example, to enter \( 3.14 \times 10^{-12} \), enter "3.14E-12".)
### Explanation of Concepts
1. **Velocity Selector:**
- A device that uses perpendicular electric and magnetic fields to separate particles based on their velocities. The fields exert forces that can balance each other, allowing only particles with a specific velocity to pass through undeflected.
2. **Circular Motion in a Magnetic Field:**
- When the electric field is removed, charged particles move in a circular path due to the magnetic force. The radius of the path helps determine properties such as the mass-to-charge ratio.
### Hints
- For part (a), use the principle that electric ( \( E \) ) and magnetic ( \( B \) ) forces balance each other: \( qE = qvB \), leading to \( v = \frac{E}{B} \).
- For part (b), use the relationship for circular motion: \( qvB = \frac{mv^2}{r} \), to find the mass-to-charge ratio. Here, \( r \) is the radius of the circle.
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