(unrealistic) E/M Forces 6. A particle of charge q = 0. 25C and mass m = 1.0kg is moving with a velocity of v = (2,0,0)m/s. The charged particle finds itself in an electric field of E = (8,8,8)N/C and a magnetic field of B = (0,0,-2)T. What will be the initial vector acceleration of the particle?
Q: total acceleration
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- At the Relativistic Heavy Ion Collider (RHIC) facility on Long Island, NY, they accelerate gold nuclei (79 protons with a total mass of 3x10-25 kg) with a very strong magnetic field (the proton has a charge of 1.6x10-19 C). If the magnetic field were 2 Tesla, what would be the cyclotron radius of the circular loop that the nuclei circle around in, assuming they go at about the speed of light, 3x108 m/s? (note, in real life, the RHIC collider is considerably larger than this because of relativistic effects!) a. 1.5 m b. 2.5 m c. 3.5 m d. 4.5 mA proton (with charge of 1.6 x 10^-19 C and mass of 1.7*10^-27 kg) traveling at a speed of 53,045,750 m/s in the + x-direction enters a region of space where there is a magnetic field of strength 0.6 T in the - z-direction. What would be the radius of the circular motion that the proton would go into if it is "trapped" in this magnetic field region?A 100-kg metallic ball at rest is being pulled by the strange magnetic field of a planet, where the force (in newtons) is given by the km function F (r) = 4p5 Where: r = distance from the planet's surface in km m = object's mass in kg k = 5.00 km5/kg The metallic ball starts at a very distant position from the planet (r → c0) and falls towards the planet. What is the potential function U (r) of the planet? Use the condition lim,. U(r) = 0. 'r→∞ What is the metallic ball's speed (in m/s) once the steel ball is one kilometer above the planet's surface? Justify your answer using your rationale and equations used.
- A cyclotron is a machine that can be used to accelerate charged particles to achieve large kinetic energies. The resulting beams of highly energetic particles then can be used for many medical applications, including Proton Therapy (a more precise form of "radiation" used in the treatment of some cancers). A description of the cyclotron can be found in section 19.3 of the text. If a proton (of mass 1.673x10-27kg) is accelerated to its maximum velocity inside a dee with radius 1.32cm (this is the radius you would use for the "r" term in the centripetal acceleration), and if the magnetic field has a magnitude of 1.84x10-2T, what is the resulting velocity of the proton in units of km/s (kilometer per second)?A proton is traveling through a region of space containing both a magnetic and electric field. At one instant in time, the velocity is U = (13500 Î + +38500) m/s and the acceleration is a = (4.39 k) x 10 m/s². If B=(9.21 k) mT, what is the magnitude of the electric field? i Save for Later N/C Submit AnswerA proton travels through a 0.75 T magnetic field in a circle with a radius of 0.30 m. What is the momentum of this proton?
- An object with a charge of +0.3 C moves through a magnetic field of strength 40 T with a velocity of 200m/s as shown. How much force does the magnetic field apply on the particle?A cyclotron is a device for accelerating charged particles to high speed as they follow an expanding spiral-like path (See LHC, NSRRC, or an MRI machine). The charged particles are subjected to both an electric field and a magnetic field. One of these fields increases the speed of the charged particles, and the other field causes them to follow a curved path. Which one does the latter? The magnetic field, since it exerts a force to the moving charge perpendicular to the charges' direction of motion. The electric field, since it exerts a force that accelerates the particle in the curved path of the facility. Not necessarily only one. Both contributes to the particles' curving of path as both exert force perpendicular to their velocity's direction. None of them. The curving of charges occur due to the design of the facility/device.A 2.00µC charge, centered at the origin of a reference frame, feels a 5.00N force on it from a 10.0µC charge located nearby, at an angle of 135° with respect to the X axis. What is the field strength and direction in polar form, of the E field caused by the 10.0µC charge at the location of the 2.00µC charge? ( labeled drawing of setup) How far away from the 2.00µC is the 10.0µC charge?
- A particle is launched from the origin on the ground with an initial velocityv = (2.40 m/s) x+ (2.00 m/s) y. The particle falls freely under earth’sgravitational field.a. Find the angle at which the particle is launched at origin. (angle made topositive x axis).b. How far does the particle move in the x direction?c. What is the particle’s velocity at this time?d. How long it stays in the airA 3.5 mC charge moves with a speed of 10,000 m/s in a magnetic field of 0.5 T. How much force is exerted on the charge?