al Two long straightwires carrying 6 A of conventional currentare connected by a three-quarter-circulararc of radius 0.0613 m. An electric field isalso present in this region, due to chargenot shown on the drawing. An electron ismoving to the right with a speed of 4x 105m/s as it passes through the center C of thearc, and at that instant the net electric andmagnetic force on the electron is zero.(Consider the charge of the electron:9. =-1.6x 10-19 C)Radius RC.Electron4.The magnitude of themagnetic field due to the three-quarter-circular arc at the center of the arc is:Bare=) The direction of the magneticfield due to the three-quarter-circular arcat the center of the arc is pointing to:5.Olnto the pageOOut of the pageOUpwardODownwardThe magnetic force acting onthe electron calculated using the formulanumber (refer to the formula sheet)6.个7.The magnitude of the magneticforce on the electron at the center of thearc can be calculated using:(1.6 x 10-19)x(4 x 10°)x(4.61 x 10-5)x(cos(90))(1.6 x 10-19)x(4 x 10°)x(4.61 x 10-)x(sin(0))(1.6 x 10-19)x(4 x 10°)x(4.61 x 10-5)x(sin(45))(1.6 x 10-19)x(4 x 10)x(4.61 x 10-5)x(sin(90))8. ( ) The magnitude of themagnetic force on the electron at thecenter of the arc is:Fmagnetic=

Given: The value of current is 6 A. The radius of three quarter circular arc is 0.0613…

Answered: Two long straight wires carrying6 A of…

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