A proton (charge q = 1.6 × 10-19 C) moving with velocity3 = (-5,0 × 10i )m/s enters a region in which the magnetic field isB = 0.30k T. The magnitude and the direction of the magnetic force acting on theproton are:Hint: 1.0 pN = 10-12 NO .15 pN, in the positive y directionO b. 1.5 pN, in the positive x directionO c. 24 pN, in the positive y directionO d. 24 pN, in thenegative y directionO e.24 pN, in the negative z direction

Answered: Image /qna-images/answer/bb68d155-5247-4da5-a794-3ec92cf88ddf.jpg

Answered: A proton (charge q = 1.6 × 10-19 C)…

Similar questions

Several electrons move at speed 5.00 x 105 m/s in a uniform magnetic field with magnitude B = 0.270 T directed downward. Find magnetic force on the electron at point c. Enter a positive value if the direction of magnetic force is out of the page and enter a negative value if the direction of magnetic force is in to the page. d 20,0 20.0° N 30.0° B 139
Problem 1: Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.25 μC charge and flies due west at a speed of 670 m/s over the Earth’s south magnetic pole, where the 8.00 × 10-5 T magnetic field points straight up. What is the magnitude of the magnetic force on the plane, in newtons?
A particle of mass 9.02 g and charge 63.5 μC moves through a uniform magnetic field, in a region where the free-fall acceleration is -9.8 m/s² without falling. The velocity of the particle is a constant 18.27 km/s, which is perpendicular to the magnetic field. What, then, is the magnetic field? Number ( i Ĵ+ i k) Units
An alpha particle (the nucleus of a helium atom), carrying a charge of 3.2 × 10−19 C moves at 5.6 × 107 m/s at a right angle to a magnetic field. If the particle experiences a force of 1.2 × 10−14 N due to the magnetic field, what is the magnitude of the magnetic field? Answer in units of T.
An electron that is moving through a uniform magnetic field has a velocity v = (46 km/s)i + 40 km/s)j when it experiences a force F = (-4.200×10-15 N)i + (4.830×10-15 N)j due to the magnetic field. If Bx = 0, calculate the magnitude of the magnetic field B. What is Bz?
An electron (electron charge = -1.60 x 10-19 C) is moving at 370000 m/s in the positive x direction. A magnetic field of 0.700 T is oriented in the positive z direction. What is the magnetic force on the electron? 4.14 x 10-14 N in the positive y direction 4.14 x 10-14 N in the negative x direction 4.14 x 10-14 N in the negative y direction 4.14 x 10-14 N in the negative z direction No magnetic force is experienced by the electron. 4.14 x 10-14 N in the positive z direction 4.14 x 10-14 N in the positive x direction
A proton moving at 3.00 x 10° m/s through a magnetic field of 1.80 T 2) experiences a magnetic force of magnitude 7.40x1013 N. a) What is the angle between the proton's velocity and the field? b) Calculate the acceleration of the proton. (charge of proton q=1.60x1019 C, mass of proton m=1.67x1027 kg)
You have placed electrons in a magnetic field. The electrons move in horizontal circles of radius 9.5 cm when their speed is 2.0×10^6 m/s. What is the magnitude and direction of the magnetic field that causes this motion?
A particle with a charge of 2μC is moving at 3 x 106m/s perpendicularly through a magnetic field with a strength of 0.05T. What is the magnitude of the force on the particle?
A particle with a charge of −1.24×10−8C is moving with instantaneous velocity v→ = (4.19×104m/s)i + (−3.85×104m/s)j. a)What is the force exerted on this particle by a magnetic field B→ = (2.80 T )i ? Enter the x, y, and z components of the force separated by commas. b)What is the force exerted on this particle by a magnetic field B→ = (2.80 T )k ? Enter the x, y, and z components of the force separated by commas.
A proton (charge q = 1.6 × 10-19 C) moving with velocity 3 = (-5.0 × 10°i)m/s enters a region in which the magnetic field is B = 0.30k T. The magnitude and the direction of the magnetic force acting on the %3D %3D %3D proton are: Hint: 1.0 pN = 10-12 N %3D a. 24 pN, in thenegative y direction b. 24 pN, in the positive y direction O c. 1.5 pN, in the positive x direction С. d. 24 pN, in the negative z direction e. 15 pN, in the positive y direction
An ELECTRON moves to the west at 4.8 x 10^7 m/s and experiences a magnetic force of 6.0 x 10-13 N upward. a). What is the magnitude of the magnetic field and b) direction (INTO or OUT) of the board of the magnetic field acting on the ELECTRON?

SEE MORE QUESTIONS