A proton moves through a uniform magnetic field (15.0i- 25.4+ 12.7k) mT. At time given by B = t1, the proton has a velocity given by V = v, i + vyj + (1.94 km/s) k and the ww magnetic force on the proton is (5.33 x 10 N) i +(3.15 x 10 NA (a) At that instant, what is v,? (b) At that instant.what F
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- A particle with positive charge q = 3.52 x 1018 C moves with a velocity v = (5î + 4ĵ – k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle, taking B = (3î + 2ĵ + k) T and E = (3î - j - 2k) V/m. (Give your answers in N for each component.) Ey = Ey = F, = (b) What angle does the force vector make with the positive x-axis? (Give your answer in degrees counterclockwise from the +x-axis.) ° counterclockwise from the +x-axis (c) What If? For what vector electric field would the total force on the particle be zero? (Give your answers in V/m for each component.) E, = V/m E, = V/m E, = V/mA particle with charge -3.00 C initially moves at v = 1.00 i ^+ 7.00 j ^ m/s. If it encounters a magnetic field B = 10.00 k ^ T, find the force on theparticle.Current I = 30 A flows in a straight wire. An ion with charge Q = 3.2e-19 C is moving toward the wire, at distant r = 0.10 m, with speed v = 5.00×106 m/s. The magnetic force on the ion is antiparallel to the current. What is the magnitude of the force? (in N) OA: 3.742×10¯ OB: 4.379x10- OC: 5.123x10- OD: 5.994x10- 17 17 17 17 Submit Answer Tries 0/12 OE: 7.013x10 17 OF: 8.205x10- 17 OG: 9.600x10" OH: 1.123×10 17 16 Send Feedback 05008HISSO
- Protons move perpendicular to a magnetic fiekd where B= 1.1 T. Their path is a circle. Calculate the number of revolutions they make each second. ( The mass of a proton is 1.67x10^-27 Kg)A charged particle with a charge to mass ratio of 5.7E8 C/kg travels on a circular path that is perpendicular to a magnetic field whose magnitude is 0.84 T. How much time does it take for the particle to complete one revolution?Problem 2: = A particle with charge +2.0 C moves through a uniform magnetic field. At one instant the velocity vector is v (2î+4ĵ + 6k) m/sec and the magnetic force on the particle is F = (41-20ĵ+ 12k) N. The x and y components of the magnetic field are equal (Bx = By). Thus, the magnetic field is given by B = B×î + B×ĵ + B₂k. What are B× and B₂? Answer: Bx = -3 T and B₂ = −4 T.
- This time I1 = 9.01, I2 = 1.40 A, and the two wires are separated by 8.41 cm. Now consider the charge q = 5.09 x 10^-6 C, located a distance of 7.00 cm to the right of wire I2, moving to the right at speed v = 66.0 m/s. What is the magnitude of the total magnetic force on this charge? 2.21E-09 N 1.11E-09 N 5.27E-09 N 3.69E-09 NThis time I1 = 5.03, I2 = 1.44 A, and the two wires are separated by 9.70 cm. Now consider the charge q = 7.27 x 10^-6 C, located a distance of 4.27 cm to the right of wire I2, moving to the right at speed v = 24.6 m/s. What is the magnitude of the total magnetic force on this charge? 1.19E-09 N 9.52E-10 N 2.49E-09 N 1.99E-09 NQ. 3: A proton moves through a uniform magnetic field given by B = (30 î – 205) mT. At a time t1, the proton has a velocity given by = the proton is FB (Vz î + (2000m/s)ĵ) and the magnetic force of (4 * 10-17N) k. At that instant, what is the velocity vx?
- Current I = 30 A flows in a straight wire. An ion with charge Q = 3.2e-19 C is moving toward the wire, at distant r = 0.10 m, with speed v = The magnetic force on the ion is antiparallel to the current. What is the magnitude of the force? (in N) 6.00×106 m/s. A: 3.682x10-17 B: 4.897x10-17 OC: 6.513x10-17 OD: 8.662x10-17 E: 1.152x10-16 OF: 1.532x10-16 OG: 2.038×10-16 OH: 2.710×10-162.4: A proton moves through a uniform magnetic field given by B = (10 i- 203 – 30k) mT. At a time ti, the proton has a velocity given by v = (v, i + v, j + (2000m/s)k ) and the magnetic force on the proton is F, = (4 • 10-i7N) i + (2 • 10-17 N) j. At that instant, what are the (i) velocity v½ and (b) velocity vy? %3D