This time I1 = 7.81, I2 = 3.46 A, and the two wires are separated by 9.30 cm. Now consider the charge q = 6.39 x 10^-6 C, located a distance of 9.33 cm to the right of wire I2, moving to the right at speed v = 63.7 m/s. What is the magnitude of the total magnetic force on this charge? A1.13E-09 NB6.43E-09 NC3.22E-09 ND1.61E-09 N The image depicts two vertical arrows labeled $ I_1 $ and $ I_2 $, representing currents flowing upwards in two parallel wires. To the right of the wire labeled $ I_2 $, there is a small circular symbol with a charge $ q $, and an arrow pointing horizontally to the right labeled $ v $, indicating the velocity of the charged particle moving perpendicular to the direction of the current.This setup suggests an exploration of magnetic fields created by current-carrying wires and their interaction with moving charges. The wires will generate magnetic fields that can exert forces on the charge $ q $, according to the right-hand rule and the Lorentz force law, which states that the force on a charged particle in a magnetic field is given by $ \mathbf{F} = q(\mathbf{v} \times \mathbf{B}) $.

Current in wire Wire separated Distance of charge from right wire

Answered: This time I1 = 7.81, I2 = 3.46 A, and…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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This time I1 = 7.81, I2 = 3.46 A, and the two wires are separated by 9.30 cm. Now consider the charge q = 6.39 x 10^-6 C, located a distance of 9.33 cm to the right of wire I2, moving to the right at speed v = 63.7 m/s. What is the magnitude of the total magnetic force on this charge?

A	1.13E-09 N
B	6.43E-09 N
C	3.22E-09 N
D	1.61E-09 N

The image depicts two vertical arrows labeled $ I_1 $ and $ I_2 $, representing currents flowing upwards in two parallel wires. To the right of the wire labeled $ I_2 $, there is a small circular symbol with a charge $ q $, and an arrow pointing horizontally to the right labeled $ v $, indicating the velocity of the charged particle moving perpendicular to the direction of the current.

This setup suggests an exploration of magnetic fields created by current-carrying wires and their interaction with moving charges. The wires will generate magnetic fields that can exert forces on the charge $ q $, according to the right-hand rule and the Lorentz force law, which states that the force on a charged particle in a magnetic field is given by $ \mathbf{F} = q(\mathbf{v} \times \mathbf{B}) $.

Expert Solution

Step 1: Determine the given variable-

Current in wire $I subscript 1 equals 7.81 space comma space I subscript 2 equals 3.46$

Wire separated $d equals 9.30 space c m space equals 0.093 space m$

Distance of charge from right wire $r equals 9.33 space c m space equals 0.0933 space m$

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