The image depicts a diagram related to electromagnetic interactions. It shows two vertical wires with current flowing upwards, labeled \( I_1 \) and \( I_2 \). To the right of the wires, there is a point labeled \( q \), representing a charged particle. An arrow labeled \( v \) extends rightward from \( q \), indicating the velocity of the charged particle.This setup illustrates the magnetic interaction between currents and moving charges, commonly discussed in physics. The currents in the wires generate magnetic fields, which can exert force on the moving charged particle \( q \). This force depends on the direction of the velocity \( v \) and the currents \( I_1 \) and \( I_2 \), as per the right-hand rule in electromagnetism. This example discusses the effect of magnetic forces on a moving charge near two wires carrying currents. Given:- Current in wire 1, \(I_1 = 8.78 \, \text{A}\)- Current in wire 2, \(I_2 = 4.29 \, \text{A}\)- The wires are separated by a distance of \(2.64 \, \text{cm}\).Consider a charge \(q = 7.16 \times 10^{-6} \, \text{C}\) located \(4.63 \, \text{cm}\) to the right of wire \(I_2\), moving to the right at speed \(v = 36.7 \, \text{m/s}\).The question is: What is the magnitude of the total magnetic force on this charge?Choices for the magnetic force on the charge:- \(5.60 \times 10^{-9} \, \text{N}\)- \(4.48 \times 10^{-9} \, \text{N}\)- \(2.69 \times 10^{-9} \, \text{N}\)- \(1.12 \times 10^{-8} \, \text{N}\)To find the magnitude of the total magnetic force, apply the formula for the magnetic force on a moving charge and consider the contributions from both wires.

Answered: Image /qna-images/answer/b47025b4-99ce-4500-bff8-02c31b2ac3d2.jpg

This time 11 = 8.78, 12 = 4.29 A, and the two wires are separated by 2.64 cm. Now consider the charge q = 7.16 x 10^-6 C, located a distance of 4.63 cm to the right of wire 12, moving to the right at speed v = 36.7 m/s. What is the magnitude of the total magnetic force on this charge? 5.60E-09 N 4.48E-09 N 2.69E-09 N 1.12E-08 N

This time 11 = 8.78, 12 = 4.29 A, and the two wires are separated by 2.64 cm. Now consider the charge q = 7.16 x 10^-6 C, located a distance of 4.63 cm to the right of wire 12, moving to the right at speed v = 36.7 m/s. What is the magnitude of the total magnetic force on this charge? 5.60E-09 N 4.48E-09 N 2.69E-09 N 1.12E-08 N

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: This time I1 = 7.81, I2 = 3.46 A, and the two wires are separated by 9.30 cm. Now consider the…

A: Current in wire Wire separated Distance of charge from right wire

Q: A proton is moving with velocity = (vx + vz ) m/s, where vx = 7.50 *105 and vz = 5.70 * 105. The…

Q: :A proton moves through a uniform magnetic field given by B = (30 î – 20ĵ) mT. At a time t1, the…

A: Given Data Uniform magnetic field is given as B→=(30.0 i^-20.0j^) mT=(30.0i^-20.0j^ )×10-3 T…

Q: A long straight horizontal wire carries a current I= 1.80 A to the left. A positive 1.00 C charge…

Q: n electron enters a magnetic field B, 0.8Tesla which is directed into the -z axis or into the page.…

A: F = q (v x B) To use this vector cross product to calculate the magnetic force on a moving electric…

Q: Problem 1. In figure below, a particle moves along a circle in a region of uniform magnetic field of…

Q: Hello, I need help with this task. It is urgent, please help! Thank you! The electron moves with…

A: The objective of the question is to calculate the angular speed of rotation of the electron, the…

Q: Refer to the figure. I1 = 1.08, I2 = 2.25 A, and the two wires are separated by 9.32 cm. Now…

Q: Consider a particle moving through a uniform magnetic fieldB= (2.2000x10^-2)T i, with initial…

A: Step 1: Given-Magnetic field is B=2.2000×10−2i^ TThe initial velocity of particle is…

Q: 34 A particle with mass m and charge q = 4.8 x10 C is accelerated from rest at point a to point b…

A: The kinetic energy is given by q V = 0.5 mv2 The radius of the path is given by where, r is the…

Q: A charged particle is moving through a uniform magnetic field of strength 3.0 T. The path it traces…

Q: A particle of charge q = 15 mC is moving with a speed of 2.4 10* m/s in the +x direction in a…

Q: A proton moves in the magnetic field B = 0.421 T with a speed of 1.4 x 107 m/s in the directions…

Q: The magnetic field in a region is given by B = (0.750 +0.210) T. At some instant, a particle with…

Q: A particle of mass m and charge q is accelerated along the +x axis (in the plane of the page) from…

A: According to the work energy theorem, the amount of work needed to change the speed of an object is…

Q: The magnetic field in a cyclotron used in proton beam cancer therapy is 0.360 T. The dees have…

A: The objective of the question is to find the maximum speed a proton can achieve in a cyclotron given…

Q: An electron moves along the z-axis with vz=3.9×107m/svz=3.9×107m/s. As it passes the origin, what…

Q: 21. An electron (q = -1.60 × 1019 C, me = 9.11 × 10–31 kg) with an instantaneous velocity v = 1.50 x…

A: (d) The direction of force is given by the Fleming's left hand rule so that it moves in clockwise…

Q: A proton moves in the magnetic field B = 0.42% T with a speed of 1.4 x 107 m/s in the directions…

Q: A wire of length e = 0.75 m is conducting a current of i = 7.5 A toward the top of the page and…

Q: (a) the x-component, (b) the y-component, and (c) the z-component of B→?

Q: Problem 14: A proton is traveling with a velocity of V = Vxit vyj, where vx = 93 m/s and vy = 49…

Q: his time I1 = 1.62, I2 = 3.20 A, and the two wires are separated by 9.23 cm. Now consider the charge…

A: Current on wires, Distance of separation between two wired, Charge,…

Q: An electron (electron charge = -1.60 x 10-19 C) is moving at 370000 m/s in the positive x direction.…

A: If a charge 'q' is moving in a magnetic field 'B' with a velocity 'v' then the force on the particle…

Q: A proton (charge q = 1.6 × 10-19 C) moving with velocity i = (-5,0 × 10°î )m/s enters a region in…

Q: An electron (q = 1.6 x 10^-19 C, m = 9.11 x 10^-31 kg) enters a cyclotron with an unknown magnetic…

Q: A long straight wire carries a 1.5 A current. An electron moves parallel to the wire at speed 3.1 x…

A: Current , I = 1.5 A Speed , v = 3.1 x 104 m/s Distance , r = 8 cm = 0.08 m To find = magnetic force…

Q: Current I = 30 A flows in a straight wire. An ion with charge Q = 3.2e-19 C is moving toward the…

A: I have first find the magnetic field at a distance r and then find the force on charged particle…

Q: The cube in the figure is 30.0 cm on the edge. Four straight segments of wire - ab, bc, cd, and da -…

Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

The image depicts a diagram related to electromagnetic interactions. It shows two vertical wires with current flowing upwards, labeled \( I_1 \) and \( I_2 \). To the right of the wires, there is a point labeled \( q \), representing a charged particle. An arrow labeled \( v \) extends rightward from \( q \), indicating the velocity of the charged particle.

This setup illustrates the magnetic interaction between currents and moving charges, commonly discussed in physics. The currents in the wires generate magnetic fields, which can exert force on the moving charged particle \( q \). This force depends on the direction of the velocity \( v \) and the currents \( I_1 \) and \( I_2 \), as per the right-hand rule in electromagnetism.

This example discusses the effect of magnetic forces on a moving charge near two wires carrying currents. Given:

- Current in wire 1, \(I_1 = 8.78 \, \text{A}\)
- Current in wire 2, \(I_2 = 4.29 \, \text{A}\)
- The wires are separated by a distance of \(2.64 \, \text{cm}\).

Consider a charge \(q = 7.16 \times 10^{-6} \, \text{C}\) located \(4.63 \, \text{cm}\) to the right of wire \(I_2\), moving to the right at speed \(v = 36.7 \, \text{m/s}\).

The question is: What is the magnitude of the total magnetic force on this charge?

Choices for the magnetic force on the charge:

- \(5.60 \times 10^{-9} \, \text{N}\)
- \(4.48 \times 10^{-9} \, \text{N}\)
- \(2.69 \times 10^{-9} \, \text{N}\)
- \(1.12 \times 10^{-8} \, \text{N}\)

To find the magnitude of the total magnetic force, apply the formula for the magnetic force on a moving charge and consider the contributions from both wires.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

This time I1 = 9.01, I2 = 1.40 A, and the two wires are separated by 8.41 cm. Now consider the charge q = 5.09 x 10^-6 C, located a distance of 7.00 cm to the right of wire I2, moving to the right at speed v = 66.0 m/s. What is the magnitude of the total magnetic force on this charge? 2.21E-09 N 1.11E-09 N 5.27E-09 N 3.69E-09 N
This time I1 = 5.03, I2 = 1.44 A, and the two wires are separated by 9.70 cm. Now consider the charge q = 7.27 x 10^-6 C, located a distance of 4.27 cm to the right of wire I2, moving to the right at speed v = 24.6 m/s. What is the magnitude of the total magnetic force on this charge? 1.19E-09 N 9.52E-10 N 2.49E-09 N 1.99E-09 N
Answer?
Two particles have the same charge (q1=q23D1.6x10-1C) and different masses undergo circular motion in a constant magnetic field (B = 0.40 T) with the same speed of 5x10° m/s. If their circular paths differ in radius by 4.9 cm, what is the difference in the mass of these two particles? m2 ml a. 8.18 x10^(-28) kg O b. 7.11 x10^(-28) kg Oc 6.27 x10^(-28) kg O d. 5.00 x10^(-28) kg O e. 9.21 x10^(-28) kg G-Guard O O
A charged particle is introduced into a uniform magnetic field Bz = 0.5 mTesla with an initial velocity vx = 1 x 106 m/s. It’s subsequent trajectory describes a circle with radius r = 2.4 cm. What is the specific charge q/m of this particle in terms of e/m = 1.67 x 1011C/kg? Select one: a. 2e/m b. 3e/m c. e/3m d. e/2m
An electron moves with velocity v =(5.0i−5.0j) ×104 m/s in a magnetic field B = (−0.73i+0.70j) T. Determine the z-component of the force on the electron. Express your answer using two significant figures.
A charged particle moves with a speed of 6.0×103 m/s perpendicularly into an uniform magnetic field of magnitude 0.20 T. The charge of the particle is 5.8 ×10-16 C, mass of the particle is 1.2 ×10-21kg. (a) What is the magnitude of the magnetic force on the particle? (b) What could be the radius of the path of the particle if it moves inside the B-field?(c) To avoid the particle being deflected by the magnetic field, (so particle can move straight through the B-field,) an electric field is applied at the same location. What is the magnitude of the E-field? HTML EditorKeyboard Shortcuts
For the moment please disregard the moving charge off to the right. The diagram above shows segments of two long straight wires, carrying currents I_1 = 9.57 A and I_2 = 1.64 A respectively. The distance between the wires is 9.01 cm. What is the force on a 1.65-cm segment of wire #2 due to the magnetic field from wire #1? 2.88E-07 N 7.48E-07 N 1.04E-06 N 5.75E-07 N
A particle with charge q enters a region with a uniform magnetic field Bthat acts in x and z directions (By = 0). The initial velocity of the particle is v = 2î +3ŷ. The force acting on the particle is given by F = q(-3 î + 2ĵ – 9k). Find the magnetic field vector B O a. B= -3î – k O b. B = 3î . O c. B= 2î + 3k O d. B= 4î – 2k O e. B= 2î – 3k