At what speed would a proton need to circle the Earth at a height of 1000 km above the equator if the Earth's magnetic field is horizontal and directed north-south, with an intensity of 4.00x 10-8 T? (The radius of the Earth is 6400 km and the charge and mass of the proton are q = 1.60x 10-19 c and mp = 1.67x 10-27 kg. Ignore relativistic corrections.)

Modern Physics
3rd Edition
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Chapter13: Nuclear Structure
Section: Chapter Questions
Problem 2Q: A proton precesses with a frequency p in the presence of a magnetic field. If the intensity of the...
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At what speed would a proton need to circle the Earth at a height of 1000 km above the equator if the Earth's magnetic field is
horizontal and directed north-south, with an intensity of 4.00x 10-8 T? (The radius of the Earth is 6400 km and the charge and mass
of the proton are q = 1.60x 10-19 c and mp = 1.67x 10-27 kg. Ignore relativistic corrections.)
Transcribed Image Text:At what speed would a proton need to circle the Earth at a height of 1000 km above the equator if the Earth's magnetic field is horizontal and directed north-south, with an intensity of 4.00x 10-8 T? (The radius of the Earth is 6400 km and the charge and mass of the proton are q = 1.60x 10-19 c and mp = 1.67x 10-27 kg. Ignore relativistic corrections.)
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