If a charge of magnitude 7.45x10-17C, with speed 4.66x106 m/s, and mass 7.12x10-25kg moves within the magnetic field of magnitude 3.96x10-2T, what is the resulting radius of the path (in meters) the particle traces out?

If a charge of magnitude 7.45x10-17C, with speed 4.66x106 m/s, and mass 7.12x10-25kg moves within the magnetic field of magnitude 3.96x10-2T, what is the resulting radius of the path (in meters) the particle traces out?

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Question

When a charged particle moves perpendicularly to the direction of a uniform magnetic field, the direction of the magnetic force is perpendicular to both the direction of the magnetic field and the direction of the velocity of the charged particle. Accordingly, the charge begins to move in a circular path. Since the direction of the magnetic force is toward the center of the circular path the charged particle moves along, the magnetic force is a centripetal force (recall centripetal forces from chapter 5 of the text, covered in PHY 2010). A schematic of such motion is shown below. The "X"s represent the magnetic field that is directed into the plane of this screen. The direction of velocity and magnetic force lie within the plane of this screen and are at right angles to one another, as shown below.

If a charge of magnitude 7.45x10^-17C, with speed 4.66x10⁶ m/s, and mass 7.12x10^-25kg moves within the magnetic field of magnitude 3.96x10^-2T, what is the resulting radius of the path (in meters) the particle traces out?

Definition Definition Force on a body along the radial direction. Centripetal force is responsible for the circular motion of a body. The magnitude of centripetal force is given by F C = m v 2 r m = mass of the body in the circular motion v = tangential velocity of the body r = radius of the circular path

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