When a charged particle moves perpendicularly to the direction of a uniform magnetic field, the direction of the magnetic force is perpendicular to both the direction of the magnetic field and the direction of the velocity of the charged particle. Accordingly, the charge begins to move in a circular path. Since the direction of the magnetic force is toward the center of the circular path the charged particle moves along, the magnetic force is a centripetal force (recall centripetal forces from chapter 5 of the text, covered in PHY 2010). A schematic of such motion is shown below. The "X"s represent the magnetic field that is directed into the plane of this screen. The direction of velocity and magnetic force lie within the plane of this screen and are at right angles to one another, as shown below. If a charge of magnitude 7.52x10-17C, with speed 4.81x106 m/s, and mass 7.13x10-25kg moves within the magnetic field of magnitude 1.21x102T, what is the resulting radius of the path (in meters) the particle traces X X X X

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Chapter1: Units, Trigonometry. And Vectors
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When a charged particle moves perpendicularly to the direction of a uniform magnetic field, the direction of
the magnetic force is perpendicular to both the direction of the magnetic field and the direction of the velocity
of the charged particle. Accordingly, the charge begins to move in a circular path. Since the direction of the
magnetic force is toward the center of the circular path the charged particle moves along, the magnetic force
is a centripetal force (recall centripetal forces from chapter 5 of the text, covered in PHY 2010). A schematic
of such motion is shown below. The "X"s represent the magnetic field that is directed into the plane of this
screen. The direction of velocity and magnetic force lie within the plane of this screen and are at right angles
to one another, as shown below.
If a charge of magnitude 7.52x10-17C, with speed 4.81x106 m/s, and mass 7.13x10 25kg moves within the
magnetic field of magnitude 1.21×10²T, what is the resulting radius of the path (in meters) the particle traces
out?
个
X X X
Transcribed Image Text:When a charged particle moves perpendicularly to the direction of a uniform magnetic field, the direction of the magnetic force is perpendicular to both the direction of the magnetic field and the direction of the velocity of the charged particle. Accordingly, the charge begins to move in a circular path. Since the direction of the magnetic force is toward the center of the circular path the charged particle moves along, the magnetic force is a centripetal force (recall centripetal forces from chapter 5 of the text, covered in PHY 2010). A schematic of such motion is shown below. The "X"s represent the magnetic field that is directed into the plane of this screen. The direction of velocity and magnetic force lie within the plane of this screen and are at right angles to one another, as shown below. If a charge of magnitude 7.52x10-17C, with speed 4.81x106 m/s, and mass 7.13x10 25kg moves within the magnetic field of magnitude 1.21×10²T, what is the resulting radius of the path (in meters) the particle traces out? 个 X X X
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