A certain half-reaction has a standard reduction potential E=+0.51 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must'redprovide at least 1.10 V of electrical power. The cell will operate under standard conditions.Note for advanced students: assume the engineer requires this half-reaction to happern lo DataHalf-ReactionE° (V)Ag+ (aq) + e- Ag (s)0.7996Is there a minimum standard reductionpotential that the half-reaction used atthe cathode of this cell can have?= OvAl3+ (aq) + 3e → Al (s)O yes, there is a minimum.%3Dred-1.676Au+ (aq) + e - Au (s)1.692If so, check the "yes" box and calculatethe minimum. Round your answer to 2decimal places. If there is no lowerlimit, check the "no" box.Au3+ (aq) + 3e Au (s)1.498O no minimumBa2+ (aq) + 2e-+ Ba (s)-2.912Br2 (1) + 2e- -2Br (aq)1.066Ca2+ (aq) + 2e + Ca (s)-2.868Cl2 (9) + 2e - 2CI- (aq)1.35827Is there a maximum standard reductionpotential that the half-reaction used atthe cathode of this cl can have?E = OvO yes, there is a maximum.redCo2+ (aq) + 2e- Co (s)-0.28Co3+ (aq) + e - Co2+ (aq)1.92If so, check the "yes" box and calculatethe maximum. Round your answer to 2decimal places. If there is no upperlimit, check the "no" box.O no maximumCr2+ (aq) + 2e - Cr (s)-0.913Cr3+ (aq) + 3e - Cr (s)-0.744Cr3+ (aq) + e - Cr2+ (aq)-0.407Cro42- (aq) + 4H20 (1) + 3e - Cr(OH)3 (s) + 50H" (aq)-0.13By using the information in the ALEKSData tab, write a balanced equationdescribing a half reaction that could beused at the cathode of this cell.Cu2+ (aq) + 2e Cu (s)0.3419Cu2+ (ag) + e- - Cut (ag)0.153Note: write the half reaction as it wouldCu* (aq) + e - Cu (s)0.521actually occur at the cathode.F2 (9) + 2e - 2F (ag)- 2F (aq)2.866Fe2+ (ag) + 2e Fe (s)--0.447Fe3+ (aq) + e - Fe2+ (ag)0.771ExplanationCheckFe3+ (aq) + 3e - Fe (s)-0.037MacBook AirFIIF12DODD00 F4F1020escF6F7F8F9F5F1F2F3@#324&*delete24689 ditions.per olo Data2H* (aq) + 2e- → H2 (g)0.0002H20 (1) + 2e- H2 (g) + 2OH (aq)-0.8277H202 (aq) + 2H* (aq) + 2e¯ → 2H20 (I)1.776I2 (s) + 2e - 21 (aq)0.53552103 (aq) + 12H+ (aq) + 10e → I2 (s) + 6H20 (I)1.195Mg2+ (aq) + 2e Mg (s)-2.372Mn2+ (aq) + 2e¯ → Mn (s)-1.185MnO2 (s) + 4H* (aq) + 2e¯ → Mn2+ (aq) + 2H20 (I)1.224MnO4 (aq) + 8H+ (aq) + 5e- → Mn2+ (aq) + 4H2O (I)1.507Mn04 (aq) + 2H20 (1) + 3e → MnO2 (s) + 40H¯ (aq)0.595HNO2 (aq) + H+ (âq) + e¯ → NO (g) + H2O (1)0.983N2 (g) + 4H2O (1) + 4e¯ → 40H (aq) + N2H4 (aq)-1.16NO3 (aq) + 4H+ (aq) + 3e- → NO (g) + 2H20 (I)0.957Na+ (aq) + e - Na (s)-2.71Ni2+ (aq) + 2e - Ni (s)-0.257O2 (g) + 4H+ (aq) + 4e → 2H20 (1)1.22902 (g) + 2H2O (1) + 4e → 40H (aq)0.401O2 (g) + 2H+ (aq) + 2e H2O2 (aq)0.695Pb2+ (aq) + 2e → Pb (s)-0.1262PBSO4 (s) + H+ (aq) + 2e → Pb (s) + HSO4 (aq)-0.3588HSO4 (aq) + 3H+ (aq) + 2e H2SO3 (aq) + H20 (1)0.172acBook AirIIF81)F7F9F10F11F12*+9.delete+ II

Answered: Image /qna-images/answer/9aa4a3a2-9c8c-4a0a-a3d2-a0773a85c4b9.jpg

A certain half-reaction has a standard reduction potential E=+0.51 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must 'red provide at least 1.10 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happer lo Data Half-Reaction Ag+ (aq) + e Ag (s) Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? O yes, there is a minimum. = Ov Al3+ (aq) + 3e- → Al (s) %3D "red Aut (ag) + e- - Au (s) If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. Au3+ (ag) + 3e Au (s) O no minimum Ba2+ (aq) + 2e - - Ba (s) Br2 (1) + 2e- - 2Br (aq) Ca2+ (aq) + 2e Ca (s) Cl2 (9) + 2e - 2CI (aq) Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cl can have? E- Ov O yes, there is a maximum. %3D red Co2+ (aq) + 2e- Co (s) If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. Co3+ (aq) + e - Co2+ (aq) Cr2+ (aq) + 2e → Cr (s) Cr3+ (aq) + 3e - Cr (s) O no maximum Cr3+ (aq) + e - Cr2+ (aq) Cro42- (aq) + 4H20 (1) + 3e - Cr(OH)3 (s) + 50H (aq) By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the cathode of this cell. Cu2+ (aq) + 2e- Cu (s) Cu2+ (ag) + e- - Cut (aq) Note: write the half reaction as it would Cu* (aq) + e - Cu (s) actually occur at the cathode. F2 (9) + 2e 2F (aq) 2. Fe2+ (aq) + 2e - Fe (s) -0. Fe3+ (aq) + e - Fe2+ (aq) 0. Explanation Check -0. Fe3+ (aq) + 3e Fe (s)

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter18: Electrochemistry

Section: Chapter Questions

Problem 18.50QE