A galvanic cell is based on the following half-reactions.                           Fe2+ (aq) + 2e-  →  Fe (s)                                EO = -0.440 V                           2 H+ (aq) + 2e-  →  H2 (g)                              EO =  0.000 V The iron compartment contains an iron electrode and [Fe2+] = 1.00 x 10-3 M.             The hydrogen compartment contains a platinum electrode , PH2 = 1.00 atm, and a 1.00 M solution of a weak acid (HA).  If the observed cell potential is 0.333 V determine Ka for the weak acid.

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Chapter18: Electrochemistry
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Problem 133CWP: Consider a galvanic cell based on the following half-reactions: a. What is the expected cell...
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A galvanic cell is based on the following half-reactions.

 

                        Fe2+ (aq) + 2e-  →  Fe (s)                                EO = -0.440 V

 

                        2 H+ (aq) + 2e-  →  H2 (g)                              EO =  0.000 V

The iron compartment contains an iron electrode and [Fe2+] = 1.00 x 10-3 M.

           

The hydrogen compartment contains a platinum electrode , PH2 = 1.00 atm, and a 1.00 M solution of a weak acid (HA).  If the observed cell potential is 0.333 V determine Ka for the weak acid.

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