A blank MO diagram is provided below. Note that the atomic orbitals are not shown here. Please answer the question below diagram. 129 025 What is the bond order of dicarbon, C2? 1 3.

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### Understanding the Molecular Orbital (MO) Diagram

A blank MO diagram is provided below. Note that the atomic orbitals are not shown here. Please answer the question below the diagram.

#### MO Diagram:
```
σ*2p [ ]  [ ]
π*2p [ ]  [ ]  [ ]  [ ]
σ2p  [ ]  [ ]
π2p  [ ]  [ ]  [ ]  [ ]
σ*2s [ ]  [ ]
σ2s  [ ]  [ ]
```

#### Question:
What is the bond order of dicarbon, C2?

**Options:**
- 0
- 1
- 2
- 3

### Explanation:

The MO diagram consists of various molecular orbitals, represented as boxes arranged vertically according to their energy levels. Each box can hold up to two electrons.

1. **σ2s and σ*2s:** These are the bonding and antibonding orbitals formed from the 2s atomic orbitals.
2. **π2p and π*2p:** These are the bonding and antibonding orbitals formed from the 2p atomic orbitals, split into two sets of degenerate orbitals.
3. **σ2p and σ*2p:** These are the bonding and antibonding orbitals formed from the σ-overlap of the 2p atomic orbitals.

To answer the question, we need to calculate the bond order of C2. The bond order is defined as:

\[ \text{Bond Order} = \frac{(\text{Number of bonding electrons}) - (\text{Number of antibonding electrons})}{2} \]

### Calculation Steps:

1. **Determine the total number of valence electrons for C2:**
   - Each carbon atom has 4 valence electrons.
   - Total valence electrons in C2: 4 + 4 = 8 electrons.

2. **Fill the MO diagram with the 8 electrons:**
   - 2 electrons in σ2s
   - 2 electrons in σ*2s
   - 2 electrons in π2p
   - 2 electrons in π2p

3. **Identify bonding and antibonding electrons:**
   - Bonding electrons: 2 (σ2s) + 2 (π2p) + 2 (π2p) = 6
Transcribed Image Text:### Understanding the Molecular Orbital (MO) Diagram A blank MO diagram is provided below. Note that the atomic orbitals are not shown here. Please answer the question below the diagram. #### MO Diagram: ``` σ*2p [ ] [ ] π*2p [ ] [ ] [ ] [ ] σ2p [ ] [ ] π2p [ ] [ ] [ ] [ ] σ*2s [ ] [ ] σ2s [ ] [ ] ``` #### Question: What is the bond order of dicarbon, C2? **Options:** - 0 - 1 - 2 - 3 ### Explanation: The MO diagram consists of various molecular orbitals, represented as boxes arranged vertically according to their energy levels. Each box can hold up to two electrons. 1. **σ2s and σ*2s:** These are the bonding and antibonding orbitals formed from the 2s atomic orbitals. 2. **π2p and π*2p:** These are the bonding and antibonding orbitals formed from the 2p atomic orbitals, split into two sets of degenerate orbitals. 3. **σ2p and σ*2p:** These are the bonding and antibonding orbitals formed from the σ-overlap of the 2p atomic orbitals. To answer the question, we need to calculate the bond order of C2. The bond order is defined as: \[ \text{Bond Order} = \frac{(\text{Number of bonding electrons}) - (\text{Number of antibonding electrons})}{2} \] ### Calculation Steps: 1. **Determine the total number of valence electrons for C2:** - Each carbon atom has 4 valence electrons. - Total valence electrons in C2: 4 + 4 = 8 electrons. 2. **Fill the MO diagram with the 8 electrons:** - 2 electrons in σ2s - 2 electrons in σ*2s - 2 electrons in π2p - 2 electrons in π2p 3. **Identify bonding and antibonding electrons:** - Bonding electrons: 2 (σ2s) + 2 (π2p) + 2 (π2p) = 6
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