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- Arrange the following sets of compounds based on the property given in increasing order. Type in the number of the compound to the corresponding roman numeral, I being the lowest and IV being the highest. Solubility in hexane CH3CH2OCH3 CH3CH2CH2OH CH3COCH3 CH3COOH 1 4Fructose and caproic acid are both molecules that contain a 6 carbon backbone. The melting point of fructose is 103°C and the melting point of caproic acid is 31.6°C. Explain why the melting points for the two molecules differ so drastically. The structures for these two molecules are provided below. CH,OH O Fructose Caproic acid но CH,OH CH3(CH2)3CH2 HO. H.H, Br H,C + "OH C-C H, H,
- x ||| IV a mixture of I and II Br ** OCH₂CH₂ CH₂CH₂OH 11 IIIanswer all pls thanks.1. Rank the following molecules in order from highest boiling point temperature to lowest boiling point temperature. Highest bp A OH OH OH E B F OH C G OH D H O Na+ Lowest bp 2. Propan-1-ol (CH3CH₂CH₂OH) and methyl ethyl ether (CH3OCH₂CH3) have the same molecular formulas but different bonding (constitutional isomers). These two molecules have drastically different boiling points: 97.5 °C for propan-1-ol and 45.32 °C for methyl ethyl ether. Draw the bond line structure of each molecule. Explain the difference in the boiling points of these molecules, using intermolecular forces. (1-3 complete sentences)
