A 8 m deep cutting has side slopes of 1½ H : 1 V. The soil was tested and found to have the following properties: c = 24.5 kN/m³, e = 0.80, 14°. Determine the factor of safety with respect to cohesion, against failure of the slope, when (i) water level in the cut rises up to full height, (ii) when water level goes down suddenly. Given S = 2.7; and for B 34°, Stability number (N) are : = Ф N 6° 0.122 7° 0.116 14° 0.074 =

Q: Maximum unsupported clay is = depth of cut in a 50 kN/m², y Y = M. (c 18 kN/m³ and $ = 30°)

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Q: (Ans.: Si(Total) = 5.75 mm). 1200 kN G.S. 1.0m 3m x 4m 2.0m 9c = 8000.kN /m²,..y = 20.kN /m³ %3D…

A: The initial pressure acting at the level of the base of the footing is equal to,  Po=γ×Df    =20×1…

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Q: A vertical cut is to be made in a saturated and submerged clay with c = 15 kN/m², Ysat = 18.5 kN/m³,…

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A: H1=10m H2=5.75m h=6m To find factor of safety against heaving

Q: Determine the coefficient of active pressure Ka. Answer:

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Q: A long natural slope in overconsolidated fissured clay of saturated unit weight 22 kN/m³, is…

A: Given data- γsaturated=22 kN/m3,i=14o,depth z=4 m,ϕ=20o. To Find- The factor of safety FOS.

Q: Refer to Figure 15.10a. For the braced cut, given H = 8 m; H, = 3 m; y, = 17.5 kN/m³; angle of…

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Q: vestigate the stability dam by computing the actors of safety against (1) sliding; (2) verturning;…

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Q: A cut is to be made in a soil having γ = 18 kN/m3, c = 40 kPa, and φ = 15°. The cut slope makes an…

A: Note: As per the policy of the company, maximum three sub-parts can be answered at a time, so, here…

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A: According to given data   A cut of 5m is made in a 10m thick layer of stiff saturated clay which is…

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A: Given- Cohesion C=15 kN/m2, ϕ=0oγ=20 kN/m3

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Q: 4.0 3.0 12 kPa Sand: m=16 kN/m³ Ø'=32* YSAT 18.81 kN/m3 GWT

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Q: If there is a layer of sand (lower layer) under artesian pressure (causes upward flow), calculate…

A: Given data:γsat,clay=120 lb/ft3γw=62.43 lb/ft3H=?

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Q: P-3 Refer to Figure, for which L, = 2.4 m, Sand L2 = 4.6 m, y = 15.7 kN/m³, Ysat = 17.3 kN/m³, and…

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Q: Show complete solution (need ASAP): ?? = 0.3 ?/??? (horizontal direction) ?? = 0.4 ?/??? (vertical…

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Q: A cut is to be made in clay for which the cohesion is 40 kN/m² and = 0. The maximum safe depth of…

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Q: " consider a braced cut excavation which is 45' deep and which has supports 17, 28' and 40'. The…

A: depth- 45'depth of support- 5',17',28' and 40'c=1100 psfγ=110 pcfspacing- 10 feetTo determine- a)…

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A: Thickness of clay (H) = 30 ft Cr = 0.035

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A: 1. Active Earth Pressure Coefficients:For the soft sand layer (ϕ1=20)…

Q: 9, = 10 kPa Fine-grained soil y=17.2 kN/m, S= 0.8. = 27°, s, = 55 kPa 1.5 m

A: The given data is: H1=8 ft H2=(12+D)ft Calculating the coefficient of earth pressure:

Q: A cut slope is to be excavated in saturated clay with sides rising at an angle a = 55° to the…

A: Given Data: γsat=115lb/ft3qu=1000lb;ft2α=55°β=35°

Q: b) What is the advantage for the Engineer in using Rankine's lateral earth pressure theory over…

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Q: The soil condition in the field is as follows: c = 20 kN/m², 6 = 20°, Y = 20 kN/m³ The maximum depth…

A: Given;Cohesion (C) = 20 kpaAngle of internal friction () = 20Unit weight of soil () = 20 kn/m3

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Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.