Given the following slope staking notes, the prismoidal correction factor in cu. Yds., to be applied to the fill volume between Stations 49+00 and 50+00 is: Basis for Cut Basis for Fill Cutslope 33.2 Sta. O24.2 5100 5000 O None of these. O 20.2 4900 48 40 s=2.5:1 ft ft L CX1 33.4 F 5.4 33.6 F 6.4 36.0 C C 5.5 FO F 3.5 R C 3.2 X2 C 4.1 34.25 FO 20

Given the following slope staking notes, the prismoidal correction factor in cu. Yds., to be applied to the fill volume between Stations 49+00 and 50+00 is: Basis for Cut Basis for Fill Cutslope 33.2 Sta. O24.2 5100 5000 O None of these. O 20.2 4900 48 40 s=2.5:1 ft ft L CX1 33.4 F 5.4 33.6 F 6.4 36.0 C C 5.5 FO F 3.5 R C 3.2 X2 C 4.1 34.25 FO 20

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Construction Surveying
List unon au vu.. disau.. c) Describe embankment geometry with figure.
Answer with complete solutio.
Civil, Rquired an right answer In a furrow irrigation system, the length of the furrow is 200 metres, the advance time is 240 minutes, and the advance equation is x = p * t_r r, where "p" and "r" are 8 and 0.7, respectively. The separations of the chosen stations from the furrow's starting are 40, 80, 120, 160, and 200 metres. (Using t as the minute and Z as the millimetre) Z = 5t 0.56 is the integrated infiltration equation. Establish the possibility for infiltration and the depth of water in the soil at each station. Determine deep percolation and runoff if the width of the furrow is 0.8 metres, the input discharge into the furrow is 1.5 litres per second, and the root depth is 90 millimetres.
Q29 Please provide justified answer asap to get a upvote
N Rod ++ 50 1+50 1+75 2.6 Complete the set of differential leveling notes in Table 2-5, and perform the arithmetic 2.5 Prepare a set of profile leveling notes for the survey in Figure 2-34. In addition to comput- ing all elevations, show the arithmetic check and the resulting error in closure. check. 5.11 4.66 3.98 1.20 1.80 TP 2 4.42 4.30 2.01 Known Elevation is 402.78 4.72 TP 1 BM 61 Elevation = %3D 396.74 FIGURE 2-34 5-35 ()
A series levelling had been down along the centre line of the proposed road the distance between each two points (100m). If the elevation of the points A, E and H after completing the project should be 31m, 30m, and 31.5m respectively and these three points connected with straight lines having uniform gradient. Calculate the depth of cut and fill for the points C and G.
Given the following set of slope staking notes, find X2: Basis for Cut Basis for Fill Cutslope O 28.8 O 22.2 25.4 32.4 Sta. 5100 5000 4900 None of these. 52 38 s=2:1 ft ft L CX1 33.4 F 7.3 33.6 F 8.6 36.2 C C 5.5 FO F 3.5 R C 3.2 X2 C 4.1 34.2 FO 19
Depth Bulk Dens. ft g/cm³ 2.046 1000 2.143 2000 2.233 3000 2.300 4000 2.353 5000 2.392 6000 2.430 7000 2.460 8000 2.482 9000 2.497 10000 2.510 11000 2.522 12000 2.533 13000 2.543 14000 2.552 15000 2.560 16000 2.567 17000 2.573 18000 2.578 19000 2.582 20000 2.585 21000 2.587 22000 2.588
Q6/ Below the elevation of points on the center of road project. If the D.L is start at elevation (25m) with ascending slope (0.5%). Find the heights of Fill and depths of cut for each points. с E F H I 100 150 200 250 300 350 400 25.7 25,2 24.8 26.6 26.8 27.2 27 60 28.0 Points A Dist. 0.0 C 26 B 50
Situation No. 10 Solve and Give the complete solutions.
A 120mx120m lot is divided into 9 equal sections. Find the volume (m3) to be excavated if the ground surface is to be leveled to elevation 10m. The elevations of the ground surface at each corner are as follows: A = 19.2m B = 15.3m C = 16.9m D = 19.5m E = 17.2m F = 17.6m G = 16.2m H = 15.1m I = 17.2m J = 18.6m K = 18.2m L = 17.5m M = 18.8m N = 17.1m O = 16.2m P = 17.9m Round your answer to 3 decimal places.