A 7.33 kg particle with velocity v = (1.80 m/s) (6.97 m/s ) is at x = 5.08 m, y = 3.64 m. It is pulled by a 5.87 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing? (a) Number i (b) Number i (c) Number i k Units Units k Units

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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A 7.33 kg particle with velocity
(1.80 m/s)i (6.97 m/s ) is at x = 5.08 m, y = 3.64 m. It is pulled by a 5.87 N force in the
negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the
rate at which the angular momentum is changing?
(a) Number i
(b) Number
(c) Number
I
i
=
k Units
k Units
k Units
>
Transcribed Image Text:A 7.33 kg particle with velocity (1.80 m/s)i (6.97 m/s ) is at x = 5.08 m, y = 3.64 m. It is pulled by a 5.87 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing? (a) Number i (b) Number (c) Number I i = k Units k Units k Units >
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