A +5.1 percent grade intersects a -2.8 percent grade at station 68+70 at an elevation of327.50 ft. Calculate the centerline elevations for the PVC, PVT, and every even 100-ftstation for a 500-ft vertical curve.

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Answered: A +5.1 percent grade intersects a -2.8…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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An equal-tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI is at station 100+20 and elevation 950 ft and the PVT is at station 105+20. Answer the following 5 questions Question 3 to Question 7. The station of the PVC is at: sta 93+20 sta 95+20 sta 97+20 sta 99+20 sta 105+20
2.) A 9% grade meets a 5% grade at station 2 + 270 of elevation 150 m. The lengths are L1 = 80 m. and L2 = 60 m. Calculate the elevation at PC, PT and at every full station.
A 591m equal tangent crest vertical curve has PVC at Sta 19+252 and at elevation 124m. The initial grade is 4.8% and the final grade is -5.97%. Determine the station of PVT.
A 850-ft equal-tangent creat vertical cuve has its PVC at station 102+00 and elevation 1000 ft. The initial grade is 3.5% and the final grade is -3%. Determine the station of the highest point of the curve O A. 106+58 O B. 72+90 O C. 49+31 O D. 78+81
A +2.5% grade meets a -1.75% grade at the station 44+25 and elevation 386.96 ft, the length of curve is 800 feet (8 stations). (1) Provide the stakeout for full stations using parabolic method STATION X g1 X (g2-g1) X2 2L Y (Elevation) PVT = PVC = (2) Determine the station and elevation at the high point of the curve
D] Calculate the centerline elevations for PVC, VPI, PVT, station 32+00, and turning point (highest or lowest point on the curve) for an 800-foot long vertical curve with a back grade (g1) of -3.5 percent that intersects the ahead grade (g2) of +2.5 percent at station 30+00 (VPI) and tangent elevation 310.000 feet.
A -1% grade meets a +3% grade at sta. 12+00 and elevation 520 ft. by a vertical curve of length 200 ft. Calculate the following: i. K and r ii. Station of PVC and PVT iii. Elevation of point at a distance, L/4, from PVC and PVT iv. station of turning point v. elevation of turning point vi. elevation of mid-point of the curve
A plus 5.0 percent grade intersects a minus 3.0 percent grade at station 4 + 10 and at an elevation of 460.60 ft. Given that a PVC station 3+00 is utilized. Determine the length of curve, PVT station, EPVC and EPVT?
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A -6% grade is followed by a 2% grade intersecting at Sta. 15+750, with an elevation of 372.25 m. The change of grade is restricted to 0.45% per 20 m station. Compute the elevation of Sta. 15+705
9
A 546m equal tangent crest vertical curve has PVC at Sta 19+274 and at elevation 136m. The initial grade is 6.14% and the final grade is -5.58%. Determine the station of PVT. Note: Do not include the + sign Sample Answer: 15980

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A +5.1 percent grade intersects a -2.8 percent grade at station 68+70 at an elevation of 327.50 ft. Calculate the centerline elevations for the PVC, PVT, and every even 100-ft station for a 500-ft vertical curve.