A 5-m length solid steel shaft is subjected to a torque of 15 kN-m. If the angular deformation of the shaft is limited to 4º, what minimum diameter is required? Also, calculate the maximum shearing stress developed. Use G = 83 GPa.

A 5-m length solid steel shaft is subjected to a torque of 15 kN-m. If the angular deformation of the shaft is limited to 4º, what minimum diameter is required? Also, calculate the maximum shearing stress developed. Use G = 83 GPa.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The compound shaft has a uniform cross-sectional area with the given length of each segment. Using the applied torque on the indicated position, determine the safe diameter of the shaft if the allow stress in each segment is shown and the free end angular deformation is limited to 2.8° Hint: 3 different diameters from stress analysis One answer of diameter from angular deformation. 90DN-m A Treactuon 75DN/m 1200N-m 3.4m 15m 2.3m Allow Torsional Segment Stress G 70 Gfa AB 89GPA BC 28GP. CD GOMPA 75 MPa 50 MPa'
A steel cantilever beam 6 m in length is subjected to a concentrated load of 120 N acting at the free end of the bar. The cross section of the beam is shown below. deep. Determine the magnitude and location of the maximum tensile and compressive bending stresses in the beam. As usual, neglect the weight of the beam. 4mm 120 N 1mm 1mm 6mm 6m 1mm 4mm
Calculate the safe shear stress value of the shaft, given that the smallest allowable diameter d of the shaft subjected to forces P and Q is given as 60 mm in the figure?
A solid circular bronze [G = 6,500 ksi] shaft, 6.0 ft long and 1.325 in. in diameter, carries a torque of 90 Ib-ft. For this shaft, determine: (a) the maximum shear stress in the shaft. (b) the magnitude of the angle of twist. Answer: (a) Tmax = psi (b) Ф%3D
4. Two solid shafts of different materials are rigidly fastened together and attached to rigid supports as shown in the figure together with the given section properties. The torque of 1000 N-m is applied at the junction of the two segments. Compute the maximum shearing stress developed in the assembly. Answer: TĄ = 5.57 MPa Ts = 22.0 MPa 3 m 1.5 m Ta Aluminum Steel 75 mm dia. T=1.0 kN•m Ga- 28 GN/m²? 50 mm dia G, - 83 GN/m?
A hollow aluminum tube used in a roof structure has an outside diameter d2= 112mm and an inside diameter d1= 80mm. The tube is 2.80m long, and the aluminum has a shear modulus of G= 28GPa.a. If the tube is twisted in pure torsion by torques acting at the ends, what is the angle of twist, in degrees,when the maximum shear stress is 52MPa?b. What diameter d, in mm, is required for a solid shaft, as shown, to resists the same torque with the same maximum stress?c. What is the ratio of the weight of the hollow tube to the weight of the solid shaft?
A 2 m long shaft is transmitting 90 kW at 150 RPM. The allowable shear stress in the material is 60 MPa. If the shaft is not allowed to twist more than 1°, then the diameter of the shaft required will be (Take G = 85 GPa)
2. A solid shaft of 150 mm radius is used to transmit torque. Find the maximum torque transmitted by the solid shaft if the maximum shear stress induced to the shaft is 45 MPa.