A 250.0-mL sample of 0.125 M Na3PO4 is mixed with 250.0 mL of 0.175 M Ca(NO3)2 to form Ca3(PO4)2. The net ionic equation for the reaction is given below:3 Ca2+(aq) + 2 PO43–(aq) ➜ Ca3(PO4)2(s)What is the concentration of the excess reactant ion in the resulting solution assuming that the volumes are additive? a.4.17 × 10–3 M PO43–b.9.38 × 10–3 M Ca2+c.5.83 × 10–2 M PO43–d.2.5 × 10–2 M Ca2+

Solution of your question is given below : Byy the reaction 3 moles of Ca ion reacts with 2 moles…

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A 250.0-mL sample of 0.125 M Na₃PO₄ is mixed with 250.0 mL of 0.175 M Ca(NO₃)₂ to form Ca₃(PO₄)₂. The net ionic equation for the reaction is given below:

3 Ca²⁺_(aq)+ 2 PO₄^3–_(aq) ➜ Ca₃(PO₄)₂_(s)

What is the concentration of the excess reactant ion in the resulting solution assuming that the volumes are additive?

a.4.17 × 10^–3 M PO₄^3–

b.9.38 × 10^–3 M Ca²⁺

c.5.83 × 10^–2 M PO₄^3–

d.2.5 × 10^–2 M Ca²⁺

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