A 25.00-mL sample of La31 was treated with excess Na2C2O4 to precipitate La2(C2O4)3, which was washed to remove excess C2O4 22 and then dissolved in acid. The oxalate from La2(C2O4)3 required 12.34 mL of 0.004 321 M KMnO4 to reach the purple end point of Reaction 6-1. Find the molarity of La31 in the unknown.

Q: Which is the limiting reagent? Write a balanced chemical equation for the reaction. How many miles…

A: Given, 2.611 grams of NiSO4*6H2O (s)

Q: Explain the stepwise production of titratable I2 from dissolved O2 in the sample.

A:

Q: 8.00 mL of 6.00 x 10-3 M Fe(NO3)3 (6.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to…

A: We have to calculate the initial moles of SCN-.

Q: Predict whether CaHPO4 will precipitate from a solution with [Ca2+] = 0.0001 M and [HPO42-] = 0.0001…

A: Solubility product quotient, Qsp is the product of the concentrations of the products, each raised…

Q: JL alt ctrl ins del NAME SECTION DATE POSTLABORATORY ASSIGNMENT "barium/calcium/magnesium" unknown…

A: Since you have posted multiple questions and have not mentioned which question you want us to solve,…

Q: Should I write my answer as a decimal

A: The dissociation constant expression would be:   Kf=1/Kd  Kd = 1/Kf  Kd = 1/1.0×1016    Kd = 1.0 ×…

Q: 100 mL of mineral water containing Mg2+ and Ca2+ is taken and titrated with 86.65 mL of 0.06120 M…

A: We know that   EDTA forms 1:1 complex with metals Mg+2 and Ca+2 Initial moles of EDTA = M*V =…

Q: A 150.0 mL sample of 0.080 M Ca2+ is titrated with 0.080 M EDTA at pH 9.00. The value of log Kf for…

A: Given that : The volume of the Ca2+ sample = 150.0 mL Molarity of the Ca2+ sample = 0.080 M Molarity…

Q: 9) Cr³+ reacts slowly with EDTA (Y4-) so it is usually analyzed using back-titration. A 100.0 mL…

A: CaCl2(aq) is a source of Ca2+(aq) that reacts with EDTA(Y4-).  The balanced equations for the…

Q: 25.00 mL 0.01000 M Ni2+ is titrated with 0.01000 M EDTA in a solution buffered topH 5.0. Given that…

A:

Q: 7.00 mL of 5.00 x 10-3 M. Fe(NO3)3 (5.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to…

A: We have to calculate the moles of Fe+3 at equilibrium.

Q: 11) What is the pM in a titration of 20.0 mL of 0.05 M Ca2 with 0.05 M EDTA if the titration is…

A:

Q: 9.00 mL of 9.00 x 10-³ M Fe(NO3)3 (9.00 times 10 to the minus 3rd power M F e (NO3)3) is added to…

A: We will first calculate the millimoles of all the reactants added and the millimoles of the final…

Q: 100.0-mL sample of a saturated PbSO4 solution was evaporated until dry. If 24 mg of solid PbSO4 was…

A: Given, Volume of slution =100 mL Mass of PbSO4 = 24mg = 24 ×10-3 g Molar mass of PbSO4 = 303.26…

Q: The following compounds are dissolved in diethyl ether and then extracted with 0.1 M HCI (pH 1)…

A:

Q: Liz CO, Lit t cO,- if the concentration of [Lit] were doubled (Say by adding a highly as LiI) what…

A: In first case , concentration of Li+ is doubled we need to determine change in concentration of CO3…

Q: Please help me with a though c

A: a) Phosphate ion (PO43-) is the most common indicator used to measure the concentration of…

Q: Name the reagent that will be used to dissolve CuS and Bi2S3.

A: CuS and Bi2S3 are insoluble sulphides having black and brownish black colour respectively.

Q: How will mistakenly using solution 1 to calibrate the spectrophotometer, instead of the blank affect…

A: A solution of FeSCN2+ will be colored. So, the concentration of FeSCN2+ at the equilibrium is…

Q: A 25 mL liquid bleach sample is diluted with water to 1000 mL in a bubble gel. 25 mL of the diluted…

A: The balanced chemical reactions involved is as follows: 2 I- + OCl- + H2O = I2 + Cl- + 2 OH- 2…

Q: 5.00 mL of 5.00 x 103 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 7.00…

A: Given: Concentration of Fe(NO3)3 taken = 5.00 × 10-3 M Volume of Fe(NO3)3 solution taken = 5.00 mL…

Q: Solution made by mixing 5mL of 0.030M Co2(SO4)3 with 40mL of 0.0120M EDTA was adjusted to pH 10.…

A: Given: Concentration of Co2(SO4)3 = 0.030 M Volume of Co2(SO4)3 = 5 mL Concentration of EDTA =…

Q: 100.0 mL of 0.0500 M EDTA was added to 50.0 mL of 0.0400 M Cu(NO3)2 at pH 6.00. The K for CuY²- is…

A: #(a): Given Kf of CuY2- = 6.0*1018  α4 at pH 6.00 = 2.3*10-5

Q: O What is the pM in a titration of 16.0 mL of 0.05 M Ca2+ with 0.05 M EDTA if the titration buffered…

A:

Q: Calculate pCd²+ at each of the given points in the titration of 50.00 mL of 0.0070 M Cd²+ with…

A:

Q: (2) A solution is 1.0x104 M in NaF, NazS, and Na3PO4. What would be the order of precipitation as a…

A: Given that  [NaF] = [Na2S] = [Na3PO4] = 1.0*10-4 it means that , concentration of  [F-] = [S2-] =…

Q: 02) Consider the titration of 20.00mL of a Ca2+0.0250mol/L solution with 0.0500mol/L EDTA. The Ca2+…

A: 2)given, initially the volume of Ca2+  = 20.00 mL concentration of Ca2+ = 0.0250 mol/L concentration…

Q: 3. In the characterization test, it was observed that Snl4 is soluble in acetone. What does this…

A:

Q: Describe how you would efficiently prepare 0.75 liters of each of the following reagents: (Mw of…

A: The solution with a defined concentration can be made by the dissolution of a certain amount of…

Q: 7.00 mL of 5.00 x 10-3 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M F e (NO3)3) is added to…

A:

Q: The equivalence point is reached when 25.00 mL of 0.100 M EDTA is titrated with 25.00 mL of 0.100 M…

A:

Q: NH3 obtained when 0.5 g of an organic compound substance was subjected to Kjeldahl's method was…

A:

Q: Make an ICE table and find equilibriun Concentration jt Kq = 100 Ź if KG =10 Equation: L-DOPA +…

A: Using the ICE table we can calculate the equilibrium concentrations.

Q: A cyanide solution with a volume of 12.99 ml was treated with 30.00 mL. of Ni solution (containing…

A:

Q: A solution containing bromate ions (BrO3) is reacted with excess iodide ions (1) producing iodine…

A: During the balancing of any chemical reaction, the law of conservation of mass is followed. It…

Q: 8.00 mL of 9.00 x 10-3 M Fe(NO3)3 (9.00 times 10 to the minus 3rd power M F e (NO3)3) is added to…

A: Volume of Fe(NO3)3 = 8ml Concentratio of Fe(NO3)3 = 9×10-3M Volume of KSCN = 5ml Concentratio of…

Q: 5.00 mL of 7.00 x 10-3 M Fe(NO3)3 (7.00 times 10 to the minus 3rd power M F e (NO3)3) is added to…

A: Volume of Fe(NO3)3 = 5ml Concentratio of Fe(NO3)3 = 7×10-3M Volume of KSCN = 9ml Concentratio of…

Q: QUESTION. a.) What is the concentration of the HClO₄ solution? b.) What is the concentration of the…

A: Given :  Mass of Na2CO3 sample = 0.2119 gm  Volume of HClO4 = 50.0 ml  Volume of NaOH used = 10.28…

Q: 6.00 mL of 5.00 x 10-3 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M F e (NO3)3) is added to…

A: Volume of Fe(NO3)3 = 6ml Concentratio of Fe(NO3)3 = 5×10-3M Volume of KSCN = 9ml Concentratio of…