9.00 mL of 8.00 x 10-³ M Fe(NO3)3 (8.00 times 10 to the minus 3rd power M F e(NO3)3) is added to 7.00 mL of 4.00 x 10-3 M KSCN (4.00 times 10 to the minus 3rdpower M KSCN) along with 7.00 mL of water. The concentration of [F e(SCN)2+] wasfound to be 3.00 x 10-4 M (3.00 times 10 to the minus 4th power M) atequilibrium. How many moles of SCN- (SCN minus) are present in the solution atequilibrium? Express your answer as a decimal number (no exponents).

Preparation of Fe(SCN)+2 is Fe+3 + SCN– -------> FeSCN+21 mole of Fe(SCN)+2 is prepared from 1…

9.00 mL of 8.00 x 10-³ M Fe(NO3)3 (8.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 7.00 mL of 4.00 x 10-3 M KSCN (4.00 times 10 to the minus 3rd power M KSCN) along with 7.00 mL of water. The concentration of [F e(SCN)²+] was found to be 3.00 x 10-4 M (3.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN- (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).

9.00 mL of 8.00 x 10-³ M Fe(NO3)3 (8.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 7.00 mL of 4.00 x 10-3 M KSCN (4.00 times 10 to the minus 3rd power M KSCN) along with 7.00 mL of water. The concentration of [F e(SCN)²+] was found to be 3.00 x 10-4 M (3.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN- (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

100%

9.00 mL of 8.00 x 10-³ M Fe(NO3)3 (8.00 times 10 to the minus 3rd power M F e
(NO3)3) is added to 7.00 mL of 4.00 x 10-3 M KSCN (4.00 times 10 to the minus 3rd
power M KSCN) along with 7.00 mL of water. The concentration of [F e(SCN)2+] was
found to be 3.00 x 10-4 M (3.00 times 10 to the minus 4th power M) at
equilibrium. How many moles of SCN- (SCN minus) are present in the solution at
equilibrium? Express your answer as a decimal number (no exponents).

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Step 1: Preparation of Fe(SCN)+2

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Step 2: Find moles of the complex formed

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Step 3: Determine the number of moles of reactants remaining

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