A 150.0 mL sample of 0.080 M Ca2+ is titrated with 0.080 M EDTA at pH 9.00. The value of log Kf for the Ca²+-EDTA complex is 10.65 and the fraction of free EDTA in the Y- form, ayt- , is 0.041 at pH 9.00. What is K!, the conditional formation constant, for Ca?+ at pH 9.00? K = What is the equivalence point volume, Ve, in milliliters? Ve = mL Calculate the concentration of Ca²+ at V = ;Ve. [Ca²+] = M %3D

A 150.0 mL sample of 0.080 M Ca2+ is titrated with 0.080 M EDTA at pH 9.00. The value of log Kf for the Ca²+-EDTA complex is 10.65 and the fraction of free EDTA in the Y- form, ayt- , is 0.041 at pH 9.00. What is K!, the conditional formation constant, for Ca?+ at pH 9.00? K = What is the equivalence point volume, Ve, in milliliters? Ve = mL Calculate the concentration of Ca²+ at V = ;Ve. [Ca²+] = M %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

stion 6 of 13
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A 150.0 mL sample of 0.080 M C is titrated with 0.080 M EDTA at pH 9.00. The value of log Kf for the C-EDTA
2+
2+
complex is 10.65 and the fraction of free EDTA in the Y*- form, ay4- , is 0.041 at pH 9.00.
What is K, the conditional formation constant, for Ca²2+ at pH 9.00?
K{ =
What is the equivalence point volume, Ve, in milliliters?
Ve =
mL
Calculate the concentration of Ca+ at V = Ve.
%3D
[Ca?+] =
M
Calculate the concentration of Ca2+ at V = Ve.

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