A 20.00 g mixture of magnesium and zinc metal reacting with excess hydrochloric acid produced 1.042 g of hydrogen gas. What is the percent zinc in the original mixture?

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**Problem Statement:**

A 20.00 g mixture of magnesium and zinc metal reacting with excess hydrochloric acid produced 1.042 g of hydrogen gas. What is the percent zinc in the original mixture? 

---

**Analysis and Solution:**

To solve this problem, we need to understand the chemical reactions involved and how to use stoichiometry to find the amount of zinc in the original mixture.

### Chemical Reactions:
1. Magnesium reacts with hydrochloric acid to form magnesium chloride and hydrogen gas:
   \[
   \text{Mg} + 2\text{HCl} \rightarrow \text{MgCl}_2 + \text{H}_2
   \]

2. Zinc reacts with hydrochloric acid to form zinc chloride and hydrogen gas:
   \[
   \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2
   \]

### Stoichiometry:
- Molar mass of \( \text{Mg} \): 24.31 g/mol
- Molar mass of \( \text{Zn} \): 65.38 g/mol
- Molar mass of \( \text{H}_2 \): 2.02 g/mol

Given:
- Total hydrogen gas produced = 1.042 g

1. **Moles of \( \text{H}_2 \) produced:**

   \[
   \text{Moles of } \text{H}_2 = \frac{1.042 \, \text{g}}{2.02 \, \text{g/mol}} = 0.516 \, \text{mol}
   \]

2. **Let \( x \) be the mass of magnesium and \( y \) be the mass of zinc.**

   - \( x + y = 20.00 \, \text{g} \)

3. **Using stoichiometry:**

   Since 1 mole of \( \text{Mg} \) or \( \text{Zn} \) produces 1 mole of \( \text{H}_2 \), use the mass ratios to solve for \( x \) and \( y \):

   - The moles of Mg that could produce 0.516 mol \( \text{H}_2 \) is given by:
     \[
     \frac{x}{24.31 \, \
Transcribed Image Text:**Problem Statement:** A 20.00 g mixture of magnesium and zinc metal reacting with excess hydrochloric acid produced 1.042 g of hydrogen gas. What is the percent zinc in the original mixture? --- **Analysis and Solution:** To solve this problem, we need to understand the chemical reactions involved and how to use stoichiometry to find the amount of zinc in the original mixture. ### Chemical Reactions: 1. Magnesium reacts with hydrochloric acid to form magnesium chloride and hydrogen gas: \[ \text{Mg} + 2\text{HCl} \rightarrow \text{MgCl}_2 + \text{H}_2 \] 2. Zinc reacts with hydrochloric acid to form zinc chloride and hydrogen gas: \[ \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \] ### Stoichiometry: - Molar mass of \( \text{Mg} \): 24.31 g/mol - Molar mass of \( \text{Zn} \): 65.38 g/mol - Molar mass of \( \text{H}_2 \): 2.02 g/mol Given: - Total hydrogen gas produced = 1.042 g 1. **Moles of \( \text{H}_2 \) produced:** \[ \text{Moles of } \text{H}_2 = \frac{1.042 \, \text{g}}{2.02 \, \text{g/mol}} = 0.516 \, \text{mol} \] 2. **Let \( x \) be the mass of magnesium and \( y \) be the mass of zinc.** - \( x + y = 20.00 \, \text{g} \) 3. **Using stoichiometry:** Since 1 mole of \( \text{Mg} \) or \( \text{Zn} \) produces 1 mole of \( \text{H}_2 \), use the mass ratios to solve for \( x \) and \( y \): - The moles of Mg that could produce 0.516 mol \( \text{H}_2 \) is given by: \[ \frac{x}{24.31 \, \
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