A 2-m clay layer in the field has a current effective stress, o= 70 kN/m2. There is a net stress increase, Ao = 180 kN/m2, due to a foundation load. Calculate the expected primary consolidation settlement. The results of a consolidation test on the clay are given below. o' (kN/m?) e 0.98 12 0.94 50 0.82 200 0.73 400 © Cengage Leaming 2014

A 2-m clay layer in the field has a current effective stress, o= 70 kN/m2. There is a net stress increase, Ao = 180 kN/m2, due to a foundation load. Calculate the expected primary consolidation settlement. The results of a consolidation test on the clay are given below. o' (kN/m?) e 0.98 12 0.94 50 0.82 200 0.73 400 © Cengage Leaming 2014

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A consolidation undrained (CU) triaxial compression test is conducted on a normally consolidated…

A: Asked: To determine the effective angle of friction () for the given CU test.Given:Consolidated…

Q: data are given from the laboratory consolidation test. e₁ = 1.10 σ= 65.0 kN/m² e₂ = σ₂=240.0 kN/m²…

A: The Compression Index (Cc) is equal to the slope of the graph of pressure versus void ratio (log…

Q: A consolidated-undrained test on a normally consolidate clay yield the following results: Confining…

Q: A normally increased from 25 to 50 kN/m². If on the similar clay the effective stress is increased…

Q: A consolidated-drained (CD) triaxial test was conducted on a normally consolidated clay. The clay…

A: Solution: 1. Given: Confining pressure σ3=σ3'=276kPa Deviator Stress σd=275kPa Major Principle…

Q: coefficient of consolidation of 20 ft2 /yr is given for the singly-drained clay layer. This layer…

Q: Consolidation of Clay: Given Exercise Figure 7.4 and the accompanying information, what is the…

A: Given, Depth of clay layer, H= 6ft Porosity of clay,n=0.629Compression index, Cc=0.82Load acting at…

Q: For a laboratory consolidation test on a clay specimen (drained on both sides) the following results…

A: P1 is equal to 50 KpaP2 is equal to 120 Kpae1&nbsp;is equal to .92e2 is equal to 0.78Time…

Q: A normally consolidated clay layer 3.38 m. thick has a void ratio of 1.07. Liquid limit is equal to…

Q: A normally consolidated clay layer 5.18 m. thick has a void ratio of 1.08. Liquid limit is equal to…

A: Given data in question Void ratio Depth Liquid limit Average stress Increase in stress To find out…

Q: A consolidated-undrained test on a normall consolidate clay yield the following results: Confining…

A: Given:- Confining pressure = 160 kPa Deviator stress = 181 kPa Pore pressure = 77 kPa To find:- From…

Q: Cc = 0.2 and An oedometer test on a saturated clay soil gave the following results: Cs = 0.04. The…

A: Vertical effective stress, Increase in vertical stress, Water content, Thickness, To find:…

Q: Given that B =1 m, L = 3 m, and Q = 110 kN, the soil characteristics given in the figure are Cs =…

A: Given - Given that B =1 m, L = 3 m, and Q = 110 kN, the soil characteristics given in the figure are…

Q: A normally consolidated clay layer 4.36 m. thick has a void ratio of 1.09. Liquid limit is equal to…

Q: A 10 m thick clay layer overlying an impermeable rock is consolidated under an overburden pressure…

A: H = 10 m = 500 kPa = 300 kPa

Q: A CD triaxial compression test conducted on a clay specimen revealed that c'=5 kPa and o'=22°. What…

Q: The results of a consolidated undrained test, in which o3 = 392 kN/m², on a normally consolidated…

A: Given : Results of a consolidated undrained test on a normally consolidated clay σ3 =…

Q: A normally consolidated clay layer 3.48 m. thick has a void ratio of 1.08. Liquid limit is equal to…

Q: Triaxial compression test (CU) is conducted on a normally consolidated clay at a confining pressure…

A: It is required to find the angle of internal friction of soil. Given data, Confining pressure = 100…

Q: A site is underlain by a saturated clay layer with thickness = 5m. A sample extracted from the…

Concept explainers

Calculation of Settlement

The vertical displacement of the structural foundation due to the loading from the superstructure is known as settlement. It is due to the reduction of air voids present in the soil. The amount of vertical displacement depends on the bearing capacity of the soil on which the foundation is laid. The effect of the settlement depends on the magnitude of settlement, uniformity, and the structural design of the structure. The maximum allowable settlement for residential and office buildings should be less than 18 mm, for industrial buildings, it is 38 mm and for commercial buildings, it is 25 mm.

Question

11.12 A 2-m clay layer in the field has a current effective stress, o= 70 kN/m. There
is a net stress increase, Ao = 180 kN/m², due to a foundation load. Calculate the
expected primary consolidation settlement. The results of a consolidation test on
the clay are given below.
o' (kN/m?)
e
0.98
12
0.94
50
0.82
200
0.73
400
© Cengage Leaming 2014

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1 Given

VIEW

Step 2 Solution

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

In general, clays tend to have a more pronounced failure: -True -False
8.2
Please help with homework problem. I will leave thumbs up!
Answer in three decimal places please
Answer in three decimal places please
7.14 For a normally consolidated clay, the following values are given: Void ratio, e k (cm/sec) 0.95 0.2 x 10-6 0.91 x 10-6 1.6 Estimate k at a void ratio of 1.1. Use Eq. (7.38). Ⓒ Cengage Learning 2014
layer. 2. A project with excavation and construction stages will take place at your site. The profile contains a saturated clay On March 1, the effective stress at point A (in the middle of the clay layer) is 150 kPa, and the overconsolidation ratio is 1. On April 1, the effective stress at point A is 140 kPa. On May 1, the effective overconsolidation ratio on May 1? Show your work and circle your answer. stress at point A is 290 kPa. What is the
Answer in three decimal places please
Adry sand is known to have an angle of internal friction equal to 36°. A triaxial test is planned, where the confining pressure will be 40 kPa. What maximum axial stress (major principal stress) should be predicted?
Borings indicate that at a Queens, NY site, the top 6 meters is a loose 2) , sand with a groundwater level at 3 meters below the ground surface. Below the sand is a 10 meter thick soft clay stratum. Assume sand unit weights are ymoist = 14 kN/cubic meter and ysat = 15 kN/cubic meter. Assume clay ysat = 19 kN/cubic meter. Calculate total, pore and effective stresses at 3, 12 and 16 meters deep.
Please design a rapid sand filter that will effectively remove 65% of thesuspended solids in a flow of 10 cubic meters per minute. The suspendedmaterial consists of particles that are perfectly spherical with a diameter of 10microns. Please use sand with an effective size of 1 mm and a porosity of 0.5.You should limit your clean bed head loss to 0.5 meters per meter. (Pease use an attachment efficiency, α of 0.75)Viscosity of water =1.0087x10-3 Ns/m2Density of water =998.23 kg/m3What are the dimensions of this filter (Depth and Surface Area)?